删除核心蓝牙连接中的PIN [英] Removing PIN in Core Bluetooth Connection

问题描述

我正在开发一款通过核心蓝牙（BLE）连接手机的应用程序。连接和数据传输工作精美，但有一个小缺陷。连接新设备时，必须在其中一个设备上输入引脚。应用程序应该是非常瞬时的，并且引脚输入会极大地中断此过程。我并不担心安全问题，而且我个人将手机连接到许多蓝牙设备而没有输入引脚，所以我只是想知道如何通过iOS api完成这项工作。

I'm working on an application that connects phones via core bluetooth (BLE). The connection and data transmission work beautifully, but there is one small imperfection. When connecting to a new device, a pin must be entered on one of the devices. The application is supposed to be very instantaneous, and the pin-input greatly interrupts this process. I'm not worried about security, and I've personally connected my phone to many bluetooth devices without entering pins, so I was just wondering how this could be done with the iOS api.

谢谢！

推荐答案

如果使用'encryptionRequired'属性指定任何外围设备的特征（ CBCharacteristicPropertyNotifyEncryptionRequired 或 CBCharacteristicPropertyIndi​​cateEncryptionRequired ）或权限（ CBAttributePermissionsReadEncryptionRequired 或 CBAttributePermissionsWriteEncryptionRequired ）然后在设备之间需要绑定。

If you specify any of your peripheral's characteristics with an 'encryptionRequired' property (CBCharacteristicPropertyNotifyEncryptionRequired or CBCharacteristicPropertyIndicateEncryptionRequired) or permissions (CBAttributePermissionsReadEncryptionRequired or CBAttributePermissionsWriteEncryptionRequired) then bonding is required between the devices.

如果设备尚未绑定，则会触发配对对话框并要求输入引脚。如果您未指定外围设备特性的任何加密属性或权限，则不会提示您配对。

If the devices aren't already bonded then this will trigger the pairing dialog and require a pin to be entered. If you don't specify any of the encryption properties or permissions on your peripheral's characteristics then you won't be prompted to pair.

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