获取文本字符串从EditText上? [英] Get text string from EditText?
本文介绍了获取文本字符串从EditText上?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
看来我无法弄清楚如何让文本串出的EditText
的。
我想用从的EditText
文本在pressing按钮。
layout.xml:
< XML版本=1.0编码=UTF-8&GT?;
< LinearLayout中的xmlns:机器人=http://schemas.android.com/apk/res/android
机器人:ID =@ + ID / popup_menu_root
机器人:后台=#FFFFFF
机器人:方向=垂直
机器人:layout_width =FILL_PARENT
机器人:layout_height =FILL_PARENT>
<按钮机器人:ID =@ + ID / popup_menu_button
机器人:文本=OK
机器人:layout_width =FILL_PARENT
机器人:layout_height =WRAP_CONTENT/>
<的EditText
机器人:ID =@ + ID / EditText上
机器人:layout_width =FILL_PARENT
机器人:layout_height =WRAP_CONTENT/>
< / LinearLayout中>
我的活动:
公共类MyClass的延伸活动{
公共字符串txtCheckin =???
私人字符串txtDescription =???
私人PopupWindow PW;
@覆盖
公共无效的onCreate(包冰柱){
super.onCreate(冰柱);
//获取LayoutInflater实例
LayoutInflater充气=(LayoutInflater)MyClass.this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
//从相应的XML文件中夸大我们的观点
最后查看布局= inflater.inflate(R.layout.popuplayout,(ViewGroup中)findViewById(R.id.popup_menu_root));
//创建一个100px的宽度和高度200像素弹出窗口
PW =新PopupWindow(布局,100,200,真);
最后的EditText edittextDescription =(EditText上)findViewById(R.id.edittext);
//设置我们的弹出动作按钮,我们有
Button按钮=(按钮)layout.findViewById(R.id.popup_menu_button);
button.setOnClickListener(新OnClickListener(){
@覆盖
公共无效的onClick(查看VV){
如果(edittextDescription.getText()!= NULL)
{
。字符串newString = edittextDescription.getText()的toString();
transmitCheck(手动,txtCheckin,1,newString);
}
其他
{
transmitCheck(手动,txtCheckin,1,???);
}
完();
}
});
}
解决方案
私人的EditText txtDescription =(EditText上)layout.findViewById(R.id.txtDescription)
。串串= txtDescription.getText()的toString();
It seems I can't figure out how to get the text string out of EditText
.
I want to use the text from the EditText
at pressing the button.
layout.xml :
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/popup_menu_root"
android:background="#FFFFFF"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >
<Button android:id="@+id/popup_menu_button"
android:text="ok"
android:layout_width="fill_parent"
android:layout_height="wrap_content" />
<EditText
android:id="@+id/edittext"
android:layout_width="fill_parent"
android:layout_height="wrap_content"/>
</LinearLayout>
My Activity :
public class MyClass extends Activity {
public String txtCheckin = "???";
private String txtDescription = "???";
private PopupWindow pw;
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
// get the instance of the LayoutInflater
LayoutInflater inflater = (LayoutInflater) MyClass.this.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
// inflate our view from the corresponding XML file
final View layout = inflater.inflate(R.layout.popuplayout, (ViewGroup)findViewById(R.id.popup_menu_root));
// create a 100px width and 200px height popup window
pw = new PopupWindow(layout, 100, 200, true);
final EditText edittextDescription = (EditText) findViewById(R.id.edittext);
// set actions to buttons we have in our popup
Button button = (Button)layout.findViewById(R.id.popup_menu_button);
button.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View vv) {
if (edittextDescription.getText() != null)
{
String newString = edittextDescription.getText().toString();
transmitCheck("MANUAL", txtCheckin, "1", newString);
}
else
{
transmitCheck("MANUAL", txtCheckin, "1", "???");
}
finish();
}
});
}
解决方案
private EditText txtDescription = (EditText) layout.findViewById(R.id.txtDescription)
String string = txtDescription.getText().toString();
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