如何成功获取外部IP [英] How to get external IP successfully

问题描述

阅读后：获取'外部'IP地址Java

代码：

public static void main(String[] args) throws IOException
{
    URL whatismyip = new URL("http://automation.whatismyip.com/n09230945.asp");
    BufferedReader in = new BufferedReader(new InputStreamReader(whatismyip.openStream()));

    String ip = in.readLine(); //you get the IP as a String
    System.out.println(ip);
}

我以为我是赢家，但我收到以下错误

I thought I was a winner but I get the following error

Exception in thread "main" java.io.IOException: Server returned HTTP response code: 403 for URL: http://automation.whatismyip.com/n09230945.asp
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
at java.net.URL.openStream(Unknown Source)
at getIP.main(getIP.java:12)

我认为这是因为服务器响应不够快，是无论如何要确保它将获得外部IP？

I think this is because the server isnt responding quick enough, is there anyway to ensure that it will get the external ip?

编辑：好吧所以它被拒绝，其他人知道另一个网站可以做同样的功能

okay so its getting rejected, anyone else know of another site that can do the same function

推荐答案

在运行以下代码之前，请先看一下： http://www.whatismyip.com/faq/automation.asp

Before you run the following code take a look at this: http://www.whatismyip.com/faq/automation.asp

public static void main(String[] args) throws Exception {

    URL whatismyip = new URL("http://automation.whatismyip.com/n09230945.asp");
    URLConnection connection = whatismyip.openConnection();
    connection.addRequestProperty("Protocol", "Http/1.1");
    connection.addRequestProperty("Connection", "keep-alive");
    connection.addRequestProperty("Keep-Alive", "1000");
    connection.addRequestProperty("User-Agent", "Web-Agent");

    BufferedReader in = 
        new BufferedReader(new InputStreamReader(connection.getInputStream()));

    String ip = in.readLine(); //you get the IP as a String
    System.out.println(ip);
}

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