使用正则表达式查找有效的IP地址 [英] Finding valid IP addresses with regex
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问题描述
我有以下字符串:
text = '10.0.0.1.1 but 127.0.0.256 1.1.1.1'
我想返回有效的IP地址,因此它只应返回 1.1 .1.1
此处 256
高于 255
且第一个IP数字太多。
and I want to return the valid IP addresses, so it should only return 1.1.1.1
here since 256
is higher than 255
and the first IP has too many numbers.
到目前为止,我有以下内容,但它不适用于 0-255
要求。
so far I have the following but it doesn't work on the 0-255
requirement.
text = "10.0.0.1.1 but 127.0.0.256 1.1.1.1"
l = []
import re
for word in text.split(" "):
if word.count(".") == 3:
l = re.findall(r"[\d{1,3}]+\.[\d{1,3}]+\.[\d{1,3}]+\.[\d{1,3}]+",word)
推荐答案
这是一个非常好的python正则表达式从字符串中获取有效IPv4 IP地址的工作:
Here is a python regex that does a pretty good job of fetching valid IPv4 IP addresses from a string:
import re
reValidIPv4 = re.compile(r"""
# Match a valid IPv4 in the wild.
(?: # Group two start-of-IP assertions.
^ # Either the start of a line,
| (?<=\s) # or preceeded by whitespace.
) # Group two start-of-IP assertions.
(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?) # First number in range 0-255
(?: # Exactly 3 additional numbers.
\. # Numbers separated by dot.
(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?) # Number in range 0-255 .
){3} # Exactly 3 additional numbers.
(?=$|\s) # End IP on whitespace or EOL.
""", re.VERBOSE | re.MULTILINE)
text = "10.0.0.1.1 but 127.0.0.256 1.1.1.1"
l = reValidIPv4.findall(text)
print(l)
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