什么是通用iPhone和iPad应用程序的构建设置 [英] What are the Build Settings for a Universal iPhone and iPad Application
问题描述
构建和接受iPad和iPhone通用应用程序的设置是什么?
What would be the settings to build and have accepted an universal app for both the iPad and iPhone?
也就是说,Project X Info中的设置是什么>构建
That is, what would be the settings in Project X Info > Build for
- 架构[ARCHS](标准(armv6)或优化(armv6 armv7)或其他)
- 有效架构[VALID_ARCHS](armv6 armv7或其他)
- 仅构建活动架构(已选中或未选中)
我们在下拉列表中选择什么(Device - 3.2 | Distribution | armv?)?
and what would we select in the dropdown (Device - 3.2|Distribution|armv?) ?
我们'在我们没有为armv7构建的构建时间收到警告,或者由于
We're either getting warnings at build time that we haven't built for armv7, or the app upload is rejected on account of
二进制文件而拒绝应用程序上传您上传的内容无效。支持iPhone时,可执行文件必须包含对armv6架构的支持。
"The binary you uploaded was invalid. When supporting iPhone, the executable must include support for the armv6 architecture".
感谢您的帮助。
推荐答案
这个网站提供了一个很好的信息关于如何制作通用二进制文件。
This site gives a good information how to make a universal binary.
http://iphonedevelopment.blogspot.com/2010/04/converting-iphone-apps-to-universal.html
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