如何解雇UIPopoverController？ [英] How to dismiss the UIPopoverController?

问题描述

我创建了一个 UIPopoverController ，并在点击 UIButton 时将其添加到视图控制器中，如下所示

   - （void）viewDidLoad 
 {
 [super viewDidLoad]; 
 controller = [[SecondViewController alloc] initWithNibName：@SecondViewControllerbundle：[NSBundle mainBundle]]; 
 popoverController = [[UIPopoverController alloc] initWithContentViewController：controller]; 
} 
 
  - （IBAction）showPopover：（UIButton *）sender 
 {
 if（[popoverController isPopoverVisible]）{
 [popoverController dismissPopoverAnimated：YES ]。 
} else {
 CGRect popRect = CGRectMake（self.btnShowPopover.frame.origin.x，
 self.btnShowPopover.frame.origin.y，
 self.btnShowPopover.frame。 size.width，
 self.btnShowPopover.frame.size.height）; 
 [popoverController presentPopoverFromRect：popRect 
 inView：self.view 
 allowedArrowDirections：UIPopoverArrowDirectionAny 
 animated：YES]; 
} 
} 
  

btnShowPopover 是 viewcontroller 中的 UIButton ， popoverController 是 UIPopoverController 。

单击按钮时， popovercontroller 显示正常。

<但是当我点击 secondviewcontroller

$ b $中的 UIButton 时，它不会被解雇b

我使用了以下代码

   - （IBAction）y：（id）sender { 
 fs = [[Firstviewcontroller alloc] initWithNibName：@FIrstscreenbundle：[NSBundle mainBundle]]; 
 [fs.popoverController dismissPopoverAnimated：TRUE]; 
} 
  

但它不起作用。

单击添加到 popovercontroller 的viewcontoller中的按钮时，如何关闭 popovercontroller ？

解决方案

您正在分配一个新的 Firstviewcontroller 实例，所以它不会忽略前一个实例的popover。

当您显示popover时需要传递旧实例：

   - （void）viewDidLoad 
 {
 [super viewDidLoad]; 
 controller = [[SecondViewController alloc] initWithNibName：@SecondViewControllerbundle：[NSBundle mainBundle]]; 
 popoverController = [[UIPopoverController alloc] initWithContentViewController：controller]; 
 [控制器setFs：self] 
} 
  

并解雇如：

   - （IBAction）y：（id）sender 
 {
 [fs.popoverController dismissPopoverAnimated：TRUE]; 
} 
  

I have created a UIPopoverController and added it to a view controller when clicking an UIButton as follows

- (void)viewDidLoad
{
    [super viewDidLoad];
    controller = [[SecondViewController alloc] initWithNibName:@"SecondViewController" bundle:[NSBundle mainBundle]];
    popoverController = [[UIPopoverController alloc] initWithContentViewController:controller];
}

- (IBAction)showPopover:(UIButton *)sender
{
    if ([popoverController isPopoverVisible]) {
        [popoverController dismissPopoverAnimated:YES];
    } else {
               CGRect popRect = CGRectMake(self.btnShowPopover.frame.origin.x,
                                self.btnShowPopover.frame.origin.y,
                                self.btnShowPopover.frame.size.width,
                                self.btnShowPopover.frame.size.height);
          [popoverController presentPopoverFromRect:popRect
                                       inView:self.view
                     permittedArrowDirections:UIPopoverArrowDirectionAny
                                     animated:YES];
    }
}

btnShowPopover is the UIButton in the viewcontroller, popoverController is the UIPopoverController.

The popovercontroller appears fine while clicking the button.

But it won't get dismissed when I click the UIButton in the secondviewcontroller

I used the following code for that

-(IBAction)y:(id)sender{
    fs =  [[Firstviewcontroller alloc] initWithNibName:@"FIrstscreen" bundle:[NSBundle mainBundle]];
    [fs.popoverController dismissPopoverAnimated:TRUE];
}

But it didn't work.

How to dismiss the popovercontroller when clicking the button in a viewcontoller that was added to the popovercontroller?

解决方案

You are allocating a new instance of Firstviewcontroller, so it won't dismiss the previous instance's popover.

You need to pass the old instance when you are displaying the popover like:

- (void)viewDidLoad
{
    [super viewDidLoad];
    controller = [[SecondViewController alloc] initWithNibName:@"SecondViewController" bundle:[NSBundle mainBundle]];
    popoverController = [[UIPopoverController alloc] initWithContentViewController:controller];
    [controller setFs:self]
}

And dismiss like:

-(IBAction)y:(id)sender
{
    [fs.popoverController dismissPopoverAnimated:TRUE];
}

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