替换iPhone中的NSDictionary中的值 [英] Replace a value in NSDictionary in iPhone

问题描述

我有一个NSDictionaryitem的数组（dataArray）。对于5名学生，它具有关键名称的david和关键标记等的85等数据。我想将david的标记替换为数组索引值的90（即0表示包含david和85的字典）。我该怎么办？

I have a array (dataArray) of NSDictionary "item". It has datas like "david" for key "name" and "85" for key "marks" etc for 5 students. I want to replace the mark of david to 90 with respect to the array index value (ie 0 for dictionary containing david and 85). How can I do it?

数组中内容的代码是

[item setobject:name forkey:@"Name"];
[item setobject:mark forkey:@"Marks"];
[dataArray addOject:item]

上面的代码进入解析，所以我有数组有5个对象（学生），他们的名字和标记，现在我想替换dataArray中第一个对象的标记。

The above code goes inside parsing, so i have array with 5 objects (students), their name and marks, now I want to replace the mark of the first object in the dataArray.

推荐答案

这是你可以做的：

NSMutableDictionary *newDict = [[NSMutableDictionary alloc] init];
NSDictionary *oldDict = (NSDictionary *)[dataArray objectAtIndex:0];
[newDict addEntriesFromDictionary:oldDict];
[newDict setObject:@"Don" forKey:@"Name"];
[dataArray replaceObjectAtIndex:0 withObject:newDict];
[newDict release];

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