比较两个相同日期/时间的NSDates [英] Compare two NSDates for same date/time

问题描述

date1 == date2 不是一种有效的比较方法吗？如果没有，那么正确的选择是什么？

Is date1 == date2 not a valid way to compare? If not, what is the correct alternative?

这是我的代码：

- (NSDate*) dateWithNoTime {
    unsigned int flags = NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit;
    NSCalendar* calendar = [NSCalendar currentCalendar];
    NSDateComponents* components = [calendar components:flags fromDate:self];
    NSDate* dateOnly = [calendar dateFromComponents:components];
    return dateOnly;
}

- (BOOL) sameDayAsDate:(NSDate*)dateToCompare {
    NSDate *date1 = [self dateWithNoTime];
    NSDate *date2 = [dateToCompare dateWithNoTime];
    return date1 == date2;       // HERE IS WHERE THINGS SEEM TO FAIL

}

推荐答案

您正在比较两个指针值。您需要使用NSDate比较方法，如：

You're comparing two pointer values. You need to use the NSDate comparison method like:

return ([date1 compare:date2] == NSOrderedSame);

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