_int64未命名类型 [英] _int64 does not name a type

问题描述

在我的 pch 文件中，我有以下定义：

In my pch file I have the following definitions:

#if (_MSC_VER < 1300)
   typedef signed char       int8_t;
   typedef signed short      int16_t;
   typedef signed int        int32_t;
   typedef unsigned char     uint8_t;
   typedef unsigned short    uint16_t;
   typedef unsigned int      uint32_t;
#else
   typedef signed __int8     int8_t;
   typedef signed __int16    int16_t;
   typedef signed __int32    int32_t;
   typedef unsigned __int8   uint8_t;
   typedef unsigned __int16  uint16_t;
   typedef unsigned __int32  uint32_t;
#endif
typedef signed __int64       int64_t;
typedef unsigned __int64     uint64_t;  

当我构建我的应用程序时，我收到错误

When I build my application I get an error at

typedef signed __int64       int64_t;
typedef unsigned __int64     uint64_t; 

表示 _int64未命名类型。可能是什么问题？

which says that _int64 does not name a type. What might be the problem?

推荐答案

添加此包含

#include <inttypes.h>

然后使用uint64_t或int64_t。

Then use uint64_t or int64_t.

见下文

#include <inttypes.h>


#if (_MSC_VER < 1300)
   typedef signed char       int8_t;
   typedef signed short      int16_t;
   typedef signed int        int32_t;
   typedef unsigned char     uint8_t;
   typedef unsigned short    uint16_t;
   typedef unsigned int      uint32_t;
#else
   typedef signed __int8     int8_t;
   typedef signed __int16    int16_t;
   typedef signed __int32    int32_t;
   typedef unsigned __int8   uint8_t;
   typedef unsigned __int16  uint16_t;
   typedef unsigned __int32  uint32_t;
#endif
typedef signed __int64       int64_t;
typedef unsigned __int64     uint64_t;  

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