CLLocationCoordinate2D不知道数组中有多少个？ [英] CLLocationCoordinate2D without knowing how many will be in the array?

问题描述

我需要使用以下内容构建数组：

I need to build an array using something like the following:

CLLocationCoordinate2D  points[4];


    points[0] = CLLocationCoordinate2DMake(41.000512, -109.050116);

    points[1] = CLLocationCoordinate2DMake(41.002371, -102.052066);

    points[2] = CLLocationCoordinate2DMake(36.993076, -102.041981);

    points[3] = CLLocationCoordinate2DMake(36.99892, -109.045267);

问题是，我永远不会知道阵列中有多少项，所以我可以指定计数。有没有办法创建一个CLLocationCoordinate2D数组，只是插入新坐标而不知道最终总数是多少？

Problem is, I will never know how many items are going to be in the array, so I can specify the count. Is there a way to create a CLLocationCoordinate2D array, and just insert new coordinates without knowing what the final total will be?

编辑：我的最终目标是使用坐标来使用需要CLLocationCoordinate2D数组的polylineWithCoordinates方法制作MKPolyline。

My final goal is to use the coordinates to make an MKPolyline, using the polylineWithCoordinates method which needs a CLLocationCoordinate2D array.

推荐答案

// unpacking an array of NSValues into memory
CLLocationCoordinate2D *points = malloc([mutablePoints count] * sizeof(CLLocationCoordinate2D));
for(int i = 0; i < [mutablePoints count]; i++) {
    [[mutablePoints objectAtIndex:i] getValue:(points + i)];
}

MKPolyline *myPolyline = [MKPolyline polylineWithCoordinates:points count:[mutablePoints count]];
free(points);

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