自定义iPhone振动的强度 [英] Intensity of custom iPhone vibration

问题描述

这是一个与相关的问题。是否有自定义振动的API iOS的？。
我能够创建自定义振动模式，但无法控制强度。

This is a question related to Are there APIs for custom vibrations in iOS?. I am able to create custom vibration patterns, but have no control over the intensity.

这是从Kevin Cao的答案中复制的，它可以启用自定义振动模式：

This is copied over from Kevin Cao's answer that enables custom vibration patterns:

NSMutableDictionary* dict = [NSMutableDictionary dictionary];
NSMutableArray* arr = [NSMutableArray array ];

[arr addObject:[NSNumber numberWithBool:YES]]; //vibrate for 2000ms
[arr addObject:[NSNumber numberWithInt:2000]];

[arr addObject:[NSNumber numberWithBool:NO]];  //stop for 1000ms
[arr addObject:[NSNumber numberWithInt:1000]];

[arr addObject:[NSNumber numberWithBool:YES]];  //vibrate for 1000ms
[arr addObject:[NSNumber numberWithInt:1000]];

[arr addObject:[NSNumber numberWithBool:NO]];    //stop for 500ms
[arr addObject:[NSNumber numberWithInt:500]];

[dict setObject:arr forKey:@"VibePattern"];
[dict setObject:[NSNumber numberWithInt:1] forKey:@"Intensity"];


AudioServicesPlaySystemSoundWithVibration(4095,nil,dict);

添加密钥的代码行 @Intensity使用 int 值不起作用，我不知道如何查看 AudioServicesPlaySystemSoundWithVibration 弄明白的方法。我需要传递什么才能真正改变强度？
现在，如果我通过1,1000,0.4或0.0001并不重要，它总是相同的强度（在带有iOS7的iPhone 4上）。 任何人都可以重新创建吗？

The line of code that adds the key @"Intensity" with an int value doesn't do the trick and I don't know how to look inside the AudioServicesPlaySystemSoundWithVibration method to figure it out. What do I have to pass to it so that it actually changes the intensity? Right now, it doesn't matter if I pass 1, 1000, 0.4 or 0.0001, it's always the same intensity (on an iPhone 4 with iOS7). Can anyone recreate this?

我希望不仅可以创建振动模式，还可以创建平滑的振动包络。 如何？

I would like to be able not only to create vibration patterns, but a smooth vibration envelope. How to?

（因为这是一个用于仪器设计的研究项目，我（还）不关心应用程序商店的限制。）

推荐答案

更改 numberWithInt 调用 numberWithFloat ，并更改强度，使其介于0和1之间。我认为使用<$ c $时很奇怪c> int 而不是 float 。

Change the numberWithInt call into numberWithFloat, and change the intensity so it's between 0 and 1. I thought it was weird when they used an int rather than a float.

#pragma mark - Custom vibration methods
-(void)invokeCustomVibrationWithStartStopTimes:(NSArray*)startStopTimes andIntensity:(float)intensity {
    BOOL startOrStop = YES;
    NSMutableArray* arr = [@[] mutableCopy];
    double time = 0;
    for (NSNumber *x in stopStartTimes) {
        [arr addObject:x]
        startOrStop = !startOrStop;
        [arr addObject:@(startOrStop)];
        time = [x doubleValue] / 1000.0;
    }
    AudioServicesPlaySystemSoundWithVibration(4095,nil,{@"VibePattern":arr,@"Intensity":@(intensity)})
    [self performSelector:@selector(stop) withObject:nil afterDelay:time];
}

-(void)stop {
    AudioServicesStopSystemSound(4095); // stop buzzing the phone
}

startStopTimes ，它应该在开始时间和停止时间之间交替。传入这个数组：

For startStopTimes, it should alternate between times started and times stopped. Passing in this array:

@[@(2000), @(1000), @(1000), @(500)]

将执行示例代码所做的事情。在这种情况下，它将启动2000毫秒，停止1000毫秒，启动1000毫秒，并停止500毫秒。

Will do what the example code did. In this case, it will start for 2000 ms, stop for 1000 ms, start for 1000 ms, and stop for 500 ms.

停止<调用/ code>来停止声音。我设置它的方式，它会在发送总时间后停止声音。

stop is called to stop the sound. The way I have it set up, it stops sounds after the total amount of time sent in.

你可能已经注意到我一直在使用数组/数字文字而不是使用 [NSArray arrayWithObjects：...，nil]; 或 [NSNumber numberWith ...]; 。这使您的代码更短。另外，我用 #pragma mark 标记了开头。用它来更好地组织它。希望它有所帮助！

You may have noticed I've been using array/number literals rather than using [NSArray arrayWithObjects: ... , nil]; or [NSNumber numberWith...];. This makes your code a lot shorter. Also, I marked the beginning with a #pragma mark. Use that to organize it better. Hope it helps!

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