如何完成笛卡尔积函数的Objective-C实现？ [英] How can I complete this Objective-C implementation of a cartesian product function?

问题描述

作为我的问题的后续跟踪这里，我试图在Objective-C中实现以下PHP函数，它将生成一个笛卡尔积：

As a follow up to my question here, I am trying to implement the following PHP function in Objective-C, which will generate a cartesian product:

function array_cartesian_product($arrays)
{
    $result = array();
    $arrays = array_values($arrays);
    $sizeIn = sizeof($arrays);
    $size = $sizeIn > 0 ? 1 : 0;
    foreach ($arrays as $array)
        $size = $size * sizeof($array);
    for ($i = 0; $i < $size; $i ++)
    {
        $result[$i] = array();
        for ($j = 0; $j < $sizeIn; $j ++)
            array_push($result[$i], current($arrays[$j]));
        for ($j = ($sizeIn -1); $j >= 0; $j --)
        {
            if (next($arrays[$j]))
                break;
            elseif (isset ($arrays[$j]))
                reset($arrays[$j]);
        }
    }
    return $result;
}

以下是我目前的情况：

-(NSArray *) array_cartesian_product:(NSArray *)arrays {

    NSMutableArray *result = [[NSMutableArray alloc] init];

    int sizeIn = [arrays count];
    int size = (sizeIn > 0) ? 1 : 0;

    for(id array in arrays)
        size *= [array count];


    for(int i = 0; i < size; i++) {

        for (int j = 0; j < sizeIn; j++) {
            [result insertObject:[arrays objectAtIndex:j] atIndex:i];
        }

        for (int j = (sizeIn - 1); j >= 0; j--) {

            // ?????

        }


    }

    return result;

}

我在尝试编写相当于PHP的下一个，当前和重置函数，因为我没有知道如何引用数组的内部指针。

I'm getting lost when trying to code the equivalent of PHP's next, current and reset functions, as I dont know how to reference the internal pointer to the array.

如何实现最后一段代码并获得等效函数？

How can I implement the last block of code and get an equivalent function?

推荐答案

NSArray *cartesianProductOfArrays(NSArray *arrays)
{
    int arraysCount = arrays.count;
    unsigned long resultSize = 1;
    for (NSArray *array in arrays)
        resultSize *= array.count;
    NSMutableArray *product = [NSMutableArray arrayWithCapacity:resultSize];
    for (unsigned long i = 0; i < resultSize; ++i) {
        NSMutableArray *cross = [NSMutableArray arrayWithCapacity:arraysCount];
        [product addObject:cross];
        unsigned long n = i;
        for (NSArray *array in arrays) {
            [cross addObject:[array objectAtIndex:n % array.count]];
            n /= array.count;
        }
    }
    return product;
}

这篇关于如何完成笛卡尔积函数的Objective-C实现？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！