如何从脚本运行IPython魔术（或定时Python脚本） [英] How to run an IPython magic from a script (or timing a Python script)

问题描述

IPython％timeit magic命令可以很好地测量运行某些Python代码所需的时间。现在，我想在Python脚本中使用类似的东西。我知道timeit模块，但它有几个缺点，例如，如何自适应地选择运行次数？即，默认代码

The IPython %timeit magic command does its job well for measuring time required to run some Python code. Now, I want to use something analogous in the Python script. I know about the timeit module, however, it has several disadvantages, for example, how to select the number of runs adaptively? i.e., the default code

import timeit
t=timeit.Timer("code(f)", "from __main__ import code,f")
t.timeit() 

运行代码数百万次。 ％timeit IPyhton magic命令会自动执行此操作。我建议我可以使用类似MATLAB代码的东西
http://www.mathworks.com/matlabcentral/fileexchange / 18798

runs the code million times. The %timeit IPyhton magic command does it automatically. I suggest that I could use something like the MATLAB code http://www.mathworks.com/matlabcentral/fileexchange/18798

自动完成所有工作（并且还会告诉函数的开销是否很大）。

that does all the job automatically (and also tells if the overhead of the function is large).

如何从Python脚本调用％timeit magic（或者可能有更好的时序解决方案）？

How can I call %timeit magic from a Python script (or maybe there is a better timing solution) ?

推荐答案

这取决于你拥有哪个版本的IPython。如果您有1.x：

It depends a bit on which version of IPython you have. If you have 1.x:

from IPython import get_ipython
ipython = get_ipython()

如果你有旧版本：

import IPython.core.ipapi  
ipython = IPython.core.ipapi.get()

或

import IPython.ipapi  
ipython = IPython.ipapi.get()

完成后，运行如下魔术命令：

Once that's done, run a magic command like this:

ipython.magic("timeit abs(-42)")

请注意，脚本必须通过 ipython 运行。

Note that the script must be run via ipython.

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