IPython Notebook：什么是默认编码？ [英] IPython Notebook: What is the default encoding?
问题描述
我使用编码utf-8创建了一个包。
I have created a package using the encoding utf-8.
调用函数时，它返回一个 DataFrame ，其中一列用utf-8编码。
When calling a function, it returns a DataFrame, with a column coded in utf-8.
在命令行使用IPython时，显示此表的内容时没有任何问题。当使用Notebook时，它崩溃并出现错误'utf8'编解码器无法解码字节0xe7 。我在下面附上了一个完整的回溯。
When using IPython at the command line, I don't have any problems showing the content of this table. When using the Notebook, it crashes with the error 'utf8' codec can't decode byte 0xe7. I've attached a full traceback below.
使用Notebook的正确编码是什么？
What is the proper encoding to work with Notebook?
UnicodeDecodeError Traceback (most recent call last)
<ipython-input-13-92c0011919e7> in <module>()
3 ver = verif.VerificacaoNA()
4 comp, total = ver.executarCompRealFisica(DT_INI, DT_FIN)
----> 5 comp
c:\Python27-32\lib\site-packages\ipython-0.13.1-py2.7.egg\IPython\core\displayhook.pyc in __call__(self, result)
240 self.update_user_ns(result)
241 self.log_output(format_dict)
--> 242 self.finish_displayhook()
243
244 def flush(self):
c:\Python27-32\lib\site-packages\ipython-0.13.1-py2.7.egg\IPython\zmq\displayhook.pyc in finish_displayhook(self)
59 sys.stdout.flush()
60 sys.stderr.flush()
---> 61 self.session.send(self.pub_socket, self.msg, ident=self.topic)
62 self.msg = None
63
c:\Python27-32\lib\site-packages\ipython-0.13.1-py2.7.egg\IPython\zmq\session.pyc in send(self, stream, msg_or_type, content, parent, ident, buffers, subheader, track, header)
557
558 buffers = [] if buffers is None else buffers
--> 559 to_send = self.serialize(msg, ident)
560 flag = 0
561 if buffers:
c:\Python27-32\lib\site-packages\ipython-0.13.1-py2.7.egg\IPython\zmq\session.pyc in serialize(self, msg, ident)
461 content = self.none
462 elif isinstance(content, dict):
--> 463 content = self.pack(content)
464 elif isinstance(content, bytes):
465 # content is already packed, as in a relayed message
c:\Python27-32\lib\site-packages\ipython-0.13.1-py2.7.egg\IPython\zmq\session.pyc in <lambda>(obj)
76
77 # ISO8601-ify datetime objects
---> 78 json_packer = lambda obj: jsonapi.dumps(obj, default=date_default)
79 json_unpacker = lambda s: extract_dates(jsonapi.loads(s))
80
c:\Python27-32\lib\site-packages\pyzmq-13.0.0-py2.7-win32.egg\zmq\utils\jsonapi.pyc in dumps(o, **kwargs)
70 kwargs['separators'] = (',', ':')
71
---> 72 return _squash_unicode(jsonmod.dumps(o, **kwargs))
73
74 def loads(s, **kwargs):
c:\Python27-32\lib\json\__init__.pyc in dumps(obj, skipkeys, ensure_ascii, check_circular, allow_nan, cls, indent, separators, encoding, default, **kw)
236 check_circular=check_circular, allow_nan=allow_nan, indent=indent,
237 separators=separators, encoding=encoding, default=default,
--> 238 **kw).encode(obj)
239
240
c:\Python27-32\lib\json\encoder.pyc in encode(self, o)
199 # exceptions aren't as detailed. The list call should be roughly
200 # equivalent to the PySequence_Fast that ''.join() would do.
--> 201 chunks = self.iterencode(o, _one_shot=True)
202 if not isinstance(chunks, (list, tuple)):
203 chunks = list(chunks)
c:\Python27-32\lib\json\encoder.pyc in iterencode(self, o, _one_shot)
262 self.key_separator, self.item_separator, self.sort_keys,
263 self.skipkeys, _one_shot)
--> 264 return _iterencode(o, 0)
265
266 def _make_iterencode(markers, _default, _encoder, _indent, _floatstr,
UnicodeDecodeError: 'utf8' codec can't decode byte 0xe7 in position 199: invalid continuation byte
推荐答案
我有最近同样的问题，确实将默认编码设置为UTF-8就可以了：
I had the same problem recently, and indeed setting the default encoding to UTF-8 did the trick:
import sys
reload(sys)
sys.setdefaultencoding("utf-8")
运行 sys.getdefaultencoding（）在我的环境中产生了'ascii'（Python 2.7.3），所以我猜这是默认设置。
Running sys.getdefaultencoding() yielded 'ascii' on my environment (Python 2.7.3), so I guess that's the default.
另见此相关问题和 Ian Bicking关于该主题的博客文章。
这篇关于IPython Notebook：什么是默认编码？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
