python pandas条件累积和 [英] python pandas conditional cumulative sum
问题描述
考虑我的数据框 df
data data_binary sum_data
2 1 1
5 0 0
1 1 1
4 1 2
3 1 3
10 0 0
7 0 0
3 1 1
我想计算 data_binary的累积总和
在连续的 1
值组中。
I want to calculate the cumulative sum of data_binary
within groups of contiguous 1
values.
第一组 1
有一个 1
和 sum_data
只有一个 1
。但是,第二组 1
的有3 1
和 sum_data
是 [1,2,3]
。
The first group of 1
's had a single 1
and sum_data
has only a 1
. However, the second group of 1
's has 3 1
's and sum_data
is [1, 2, 3]
.
我尝试过使用 np.where(df ['data_binary'] == 1,df ['data_binary']。cumsum(),0)
但返回
array([1, 0, 2, 3, 4, 0, 0, 5])
这不是我想要的。
推荐答案
你想拿走累计金额 data_binary
并减去最近的累积金额,其中 data_binary
为零。
you want to take the cumulative sum of data_binary
and subtract the most recent cumulative sum where data_binary
was zero.
b = df.data_binary
c = b.cumsum()
c.sub(c.mask(b != 0).ffill(), fill_value=0).astype(int)
0 1
1 0
2 1
3 2
4 3
5 0
6 0
7 1
Name: data_binary, dtype: int64
解释
Explanation
让我们先来看看每一步都是sid并排
Let's start by looking at each step side by side
cols = ['data_binary', 'cumulative_sum', 'nan_non_zero', 'forward_fill', 'final_result']
print(pd.concat([
b, c,
c.mask(b != 0),
c.mask(b != 0).ffill(),
c.sub(c.mask(b != 0).ffill(), fill_value=0).astype(int)
], axis=1, keys=cols))
data_binary cumulative_sum nan_non_zero forward_fill final_result
0 1 1 NaN NaN 1
1 0 1 1.0 1.0 0
2 1 2 NaN 1.0 1
3 1 3 NaN 1.0 2
4 1 4 NaN 1.0 3
5 0 4 4.0 4.0 0
6 0 4 4.0 4.0 0
7 1 5 NaN 4.0 1
cumulative_sum
是 data_binary
为零的行,不要重置总和。这就是这个解决方案的动力。当 data_binary
为零时,我们如何重置总和?简单!我将 data_binary
为零的累积和切片并转发填充值。当我得到这个和累积金额之间的差异时,我已经有效地重置了总和。
The problem with cumulative_sum
is that the rows where data_binary
is zero, do not reset the sum. And that is the motivation for this solution. How do we "reset" the sum when data_binary
is zero? Easy! I slice the cumulative sum where data_binary
is zero and forward fill the values. When I take the difference between this and the cumulative sum, I've effectively reset the sum.
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