XQuery嵌套循环的自动增量辅助索引var(w。动态计数) [英] Autoincremental auxiliar index var for XQuery nested loops (w. dynamical count)
问题描述
我想要一个解决方案,如何在xQuery中保存一个真正的循环计数器作为Java,而不是我的特定简化演示的解决方法。我知道在xQuery 3.0中有一个用于FLOWR结构的计数保留字,但是它的无用的前Saxon 9.something。这是我的例子。
I want a solution for udnerstanding how to hold a real loop counter as Java in xQuery, not a workaround for my particular simplified demo. I know in xQuery 3.0 there is a count reserved word for FLOWR structures but its useless pre-Saxon 9.something. Here my example.
for $elem at $x in /Data/* return element Elem {
attribute Name {concat('_',$x,'.',name($elem))},
(: ...10 lines of code... :)
for $subelem at $y in $elem/*
(: ...5 lets... :)
return element SubElemen {
attribute Name {concat('_',$x,'.',$y,'_',name($subelement))},
(...20 lines of other attrs and elements ...)
for $subsubelem at $z in $subElem/SubSubElement
let $absIterIndex := 'THIS IS WHAT IM LOOKING'
let $subSubElemName := concat('_',$absIterIndex,'_',name($subElem))
return
element SubSubElem {
attribute Name {$subsubelem},
(..100 lines more playing with $x, $y, $absIterIndex, all lets for that iteration, attributes depending on them...)
输出是这样的(真实数据隐藏和简化)
The output is something like this (real data hidden and simplified)
<Elem Name="_1.Name">
<SubElem Name="_1.1_Name">
<SubSubElem Name="_1.First"/>
<SubSubElem Name="_2.Second"/>
<SubSubElem Name="_3.Third"/>
</SubElem Name="_1.1_Name">
<SubElem Name="_1.2_Name">
<SubSubElem Name="_4.Fourth"/>
<SubSubElem Name="_5.Fifth"/>
<SubSubElem Name="_6.Sixth"/>
<SubSubElem Name="_7.Seventh"/>
</SubElem Name="_1.1_Name">
<Elem Name="_2.Name">
<SubElem Name="_2.1_Name">
<SubSubElem Name="_8.Eighth"/>
<SubSubElem Name="_9.Ninth"/>
<SubSubElem Name="_10.Tenth"/>
<SubSubElem Name="_11.Eleventh"/>
</SubElem Name="_2.1_Name">
<SubElem Name="_2.2_Name"/>
</Elem Name="_2.Name">
<Elem Name="_3.Name">
<SubElem Name="_3.1_Name">
<SubSubElem Name="_12.Twelven"/>
</SubElem Name="_3.1_Name">
<SubElem Name="_3.2_Name"/>
</Elem Name="_3.Name">
这是上一个问题的扩展 XQuery嵌套循环的Autoincremental辅助索引变量,我接受了xQuery 3.0计数器的解决方案,然后提出了另一种选择手动完成它。但是我知道我认为这种观点是不同的,更具体,并且有一个新的例子。如果您认为应删除它,请告诉我。
This is a extension of a previous question Autoincremental auxiliar index var for XQuery nested loops, which I accepted the solution for the xQuery 3.0 counter, and then propose an alternative for manually doing it. But know i think the perspective is different and more concrete, and with a new example. If you think it should be deleted just tell it to me.
推荐答案
新问题 - 新答案。
New question - new answer.
但原则保持不变:首先产生无编号的结果,然后应用编号。这可能需要重写结果。
But the principle remains the same: produce an unnumbered result first, then apply the numbering. This may require rewriting the result.
插入代码而不是下面的XML注释。
Insert your code instead of the XML comment below.
declare function local:renumber($number, $string)
{
replace($string, 'THIS IS WHAT IM LOOKING', string($number))
};
declare function local:renumber($subSubElems, $number, $nodes)
{
for $node in $nodes
return
typeswitch ($node)
case attribute() return attribute {node-name($node)} {local:renumber($number, $node)}
case processing-instruction() return processing-instruction {name($node)} {local:renumber($number, $node)}
case comment() return comment {local:renumber($number, $node)}
case text() return text {local:renumber($number, $node)}
default (: element() :) return
element {node-name($node)}
{
local:renumber
(
$subSubElems,
if ($subSubElems[. is $node]) then count($subSubElems[. << $node]) + 1 else $number,
($node/@*, $node/node())
)
}
};
let $result := <result>{<!-- your code here -->}</result>
return local:renumber($result//SubSubElem, 0, $result/node())
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