Java - 迭代列表中的每两个元素 [英] Java - Iterating over every two elements in a list

问题描述

在同时处理2个元素时迭代列表的最佳方法是什么？

What's the best way to iterate over a list while processing 2 elements at the same time?

示例：

List<String> strings = Arrays.asList("item 1", "item 2", "item 3", "item 4");
for(int i = 0; i < strings.size(); i++){
    String first = strings.get(i);
    String second = null;
    if(strings.size() > i + 1){
        second = strings.get(i + 1);
    }
    System.out.println("First [" + first + "] - Second [" + second + "]");
}

结果：

First [item 1] - Second [item 2]
First [item 2] - Second [item 3]
First [item 3] - Second [item 4]
First [item 4] - Second [null]

我想实现：

First [item 1] - Second [item 2]
First [item 3] - Second [item 4]

推荐答案

只需增加 i by 2：

for(int i = 0; i < strings.size(); i += 2) {

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