如何在python xml.etree.ElemenTree中删除迭代器内的节点 [英] How to remove a node inside an iterator in python xml.etree.ElemenTree

问题描述

如何删除当前节点，同时通过 getiterator（）函数从根遍历所有节点？

How to remove the current node, while iterating through all nodes from root by getiterator() function?

import xml.etree.ElementTree as ET
tree = ET.parse('file.xml')
root = tree.getroot()

for node in root.getiterator():
     #if some condition:
        #remove(node)

推荐答案

您不能在不知道父节点的情况下删除节点，但 xml.etree 包不能没有办法从给定节点访问父节点。

You can't remove nodes without knowing the parent, but the xml.etree package doesn't give you any way to access a parent from a given node.

唯一的方法是匹配父节点：

The only way around this is matching the parent node instead:

for node in root.getiterator():
    if some_condition_matches_parent:
        for child in node.getiterator():
            if some_condition_matches_child:
                node.remove(child)

如果切换到 lxml library（实现相同的API，但是通过其他增强功能），可以从任何给定节点检索父节点：

If you switch to the lxml library (which implements the same API, but with additional enhancements), you can retrieve the parent node from any given node:

node.getparent().remove(node)

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