使用推断(?)类型克隆std :: iter :: Map [英] Cloning a std::iter::Map with inferred (?) type
问题描述
我无法以紧凑的方式克隆地图:
I'm having trouble cloning a Map in a compact way:
extern crate itertools_num;
use itertools_num::linspace;
fn main() {
// 440Hz as wave frequency (middle A)
let freq: f64 = 440.0;
// Time vector sampled at 880 times/s (~Nyquist), over 1s
let delta: f64 = 1.0 / freq / 2.0;
let time_1s = linspace(0.0, 1.0, (freq / 2.0) as usize)
.map(|sample| { sample * delta});
let sine_440: Vec<f64> = time_1s.map(|time_sample| {
(freq * time_sample).sin()
}).collect();
let sine_100: Vec<f64> = time_1s.map(|time_sample| {
(100.0 * time_sample).sin()
}).collect();
}
我用这段代码得到的错误是
The error I get with this code is
`time_1s` moved here because it has type `std::iter::Map<itertools_num::Linspace<f64>, [closure@examples/linear_dft.rs:12:14: 12:40 delta:&f64]>`, which is non-copyable
这是可以理解的,但如果我尝试使用 time_1s.clone()
,我会得到
which is understandable, but if I try to use time_1s.clone()
instead, I get
note: the method `clone` exists but the following trait bounds were not satisfied: `[closure@examples/linear_dft.rs:12:14: 12:40 delta:_] : std::clone::Clone`
error: the type of this value must be known in this context
(freq * time_sample).sin()
这也是可以理解的,但在(freq * time_sample).sin()
>让foo:f64 在关闭之前返回它没有任何效果。
which is also understandable, but storing (freq * time_sample).sin()
in a let foo: f64
inside the closure before returning it doesn't have any effect.
在这样的情况下我该怎么办?这个?我想做的就是不止一次使用时间向量。
What am I supposed to do in a situation like this? All I wanted to do was use the time vector more than once.
推荐答案
使用 time_1s的一种方法
两次是同时进行并在最后解压缩:
One way to use time_1s
twice is to do both together and unzip at the end:
extern crate itertools_num;
use itertools_num::linspace;
fn main() {
// 440Hz as wave frequency (middle A)
let freq: f64 = 440.0;
// Time vector sampled at 880 times/s (~Nyquist), over 1s
let delta: f64 = 1.0 / freq / 2.0;
let time_1s = linspace(0.0, 1.0, (freq / 2.0) as usize)
.map(|sample| { sample * delta});
let (sine_440, sine_100): (Vec<f64>, Vec<f64>) = time_1s.map(|time_sample| {
((freq * time_sample).sin(),
(100.0 * time_sample).sin())
}).unzip();
}
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