如何将以下json字符串转换为java对象？ [英] How to convert the following json string to java object?

问题描述

我想将以下JSON字符串转换为java对象：

I want to convert the following JSON string to a java object:

String jsonString = "{
"libraryname":"My Library",
"mymusic":[{"Artist Name":"Aaron","Song Name":"Beautiful"},
{"Artist Name":"Britney","Song Name":"Oops I did It Again"},
{"Artist Name":"Britney","Song Name":"Stronger"}]}"

我的目标是轻松访问：

(e.g. MyJsonObject myobj = new MyJsonObject(jsonString)
myobj.mymusic[0].id would give me the ID, myobj.libraryname gives me "My Library").

我听说过杰克逊，但我不确定如何使用它来装入json字符串我由于涉及mymusic列表，它不仅仅是关键值对。我怎么能用杰克逊来完成这个呢？或者如果杰克逊不是最好的话，我能有一些更简单的方法吗？

I've heard of Jackson, but I am unsure how to use it to fit the json string I have since its not just key value pairs due to the "mymusic" list involved. How can I accomplish this with Jackson or is there some easier way I can accomplish this if Jackson is not the best for this?

推荐答案

无需为GSON服务;杰克逊可以做普通地图/列表：

No need to go with GSON for this; Jackson can do either plain Maps/Lists:

ObjectMapper mapper = new ObjectMapper();
Map<String,Object> map = mapper.readValue(json, Map.class);

或更方便的JSON树：

or more convenient JSON Tree:

JsonNode rootNode = mapper.readTree(json);

顺便说一下，没有理由不能实际创建Java类并且这样做（IMO） ）更方便：

By the way, there is no reason why you could not actually create Java classes and do it (IMO) more conveniently:

public class Library {
  @JsonProperty("libraryname")
  public String name;

  @JsonProperty("mymusic")
  public List<Song> songs;
}
public class Song {
  @JsonProperty("Artist Name") public String artistName;
  @JsonProperty("Song Name") public String songName;
}

Library lib = mapper.readValue(jsonString, Library.class);

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