杰克逊序列化:忽略空值(或null) [英] Jackson serialization: ignore empty values (or null)
问题描述
我目前正在使用jackson 2.1.4,当我将对象转换为JSON字符串时,我在忽略字段时遇到了一些麻烦。
I'm currently using jackson 2.1.4 and I'm having some trouble ignoring fields when I'm converting an object to a JSON string.
这是我的作为要转换的对象的类:
Here's my class which acts as the object to be converted:
public class JsonOperation {
public static class Request {
@JsonInclude(Include.NON_EMPTY)
String requestType;
Data data = new Data();
public static class Data {
@JsonInclude(Include.NON_EMPTY)
String username;
String email;
String password;
String birthday;
String coinsPackage;
String coins;
String transactionId;
boolean isLoggedIn;
}
}
public static class Response {
@JsonInclude(Include.NON_EMPTY)
String requestType = null;
Data data = new Data();
public static class Data {
@JsonInclude(Include.NON_EMPTY)
enum ErrorCode { ERROR_INVALID_LOGIN, ERROR_USERNAME_ALREADY_TAKEN, ERROR_EMAIL_ALREADY_TAKEN };
enum Status { ok, error };
Status status;
ErrorCode errorCode;
String expiry;
int coins;
String email;
String birthday;
String pictureUrl;
ArrayList <Performer> performer;
}
}
}
以下是我如何转换它:
ObjectMapper mapper = new ObjectMapper();
mapper.setVisibility(PropertyAccessor.FIELD, Visibility.ANY);
JsonOperation subscribe = new JsonOperation();
subscribe.request.requestType = "login";
subscribe.request.data.username = "Vincent";
subscribe.request.data.password = "test";
Writer strWriter = new StringWriter();
try {
mapper.writeValue(strWriter, subscribe.request);
} catch (JsonGenerationException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (JsonMappingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Log.d("JSON", strWriter.toString())
这是输出:
{"data":{"birthday":null,"coins":null,"coinsPackage":null,"email":null,"username":"Vincent","password":"test","transactionId":null,"isLoggedIn":false},"requestType":"login"}
如何避免这些空值?我只想获取订阅目的所需的信息!
How can I avoid those null values? I only want to take required information for the "subscription" purpose!
这正是我正在寻找的输出:
Here's exactly the output that I'm looking for:
{"data":{"username":"Vincent","password":"test"},"requestType":"login"}
我也试过@JsonInclude(Include.NON_NULL)并将我的所有变量都置为null,但它也没有用!感谢您的帮助!
I also tried @JsonInclude(Include.NON_NULL) and put all my variables to null, but it didn't work either! Thanks for your help guys!
推荐答案
您的注释位置错误 - 它需要在课堂上,而不是领域。即:
You have the annotation in the wrong place - it needs to be on the class, not the field. i.e:
@JsonInclude(Include.NON_NULL) //or Include.NON_EMPTY, if that fits your use case
public static class Request {
// ...
}
如上所述在评论中,在版本2.x +中,此注释的语法是:
As noted in comments, in version 2.x+ the syntax for this annotation is:
@JsonSerialize(include = JsonSerialize.Inclusion.NON_NULL) // or JsonSerialize.Inclusion.NON_EMPTY
另一个选项是配置 ObjectMapper
直接,只需调用
mapper.setSerializationInclusion(Include.NON_NULL);
The other option is to configure the ObjectMapper
directly, simply by calling
mapper.setSerializationInclusion(Include.NON_NULL);
(为了记录,我认为这个答案的受欢迎程度表明这个注释应该适用于逐个字段* ahem @fasterxml *)
(for the record, I think the popularity of this answer is an indication that this annotation should be applicable on a field-by-field basis *ahem @fasterxml*)
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