使用jackson删除JSON元素 [英] Removing JSON elements with jackson

问题描述

我有一个特定的JSON节点，对应于导入org.codehaus.jackson.JsonNode，而不是
import org.codehaus.jackson.map.JsonNode。

I've a particular JSON Node that corresponds to import org.codehaus.jackson.JsonNode, and not import org.codehaus.jackson.map.JsonNode.

[
    {
        "givenName": "Jim",
        "formattedName": "jimJackson",
        "familyName": null,
        "middleName": "none",
        "honorificPrefix": "mr",
        "honorificSuffix": "none"
    },
    {
        "givenName": "john",
        "formattedName": "johnLasher",
        "familyName": null,
        "middleName": "none",
        "honorificPrefix": "mr",
        "honorificSuffix": "none"
    },
    {
        "givenName": "carlos",
        "formattedName": "carlosAddner",
        "familyName": null,
        "middleName": "none",
        "honorifiPrefix": "mr",
        "honorificSuffix": "none"
    },
    {
        "givenName": "lisa",
        "formattedName": "lisaRay",
        "familyName": null,
        "middleName": "none",
        "honorificPrefix": "mrs",
        "honorificSuffix": "none"
    },
    {
        "givenName": "bradshaw",
        "formattedName": "bradshawLion",
        "familyName": null,
        "middleName": "none",
        "honorificPrefix": "mr",
        "honorificSuffix": "none"
    },
    {
        "givenName": "phill",
        "formattedName": "phillKane",
        "familyName": null,
        "middleName": "none",
        "honorificPrefix": "mr",
        "honorificSuffix": "none"
    },
    {
        "givenName": "Gabriel",
        "formattedName": "gabrielMoosa",
        "familyName": null,
        "middleName": "none",
        "honorificPrefix": "mr",
        "honorificSuffix": "none"
    }
]

我想删除familyName和middleName来自上述数组的所有JSON节点。有没有办法实现这个目标？

I want to remove the "familyName" and "middleName" from all the JSON nodes of the above array. Is there any way to achieve this?

推荐答案

我没有对此进行过测试，但我认为这样的事情会做你想要的：

I haven't tested this, but I think something like this would do what you want:

import org.codehaus.jackson.node.ObjectNode;
// ...
for (JsonNode personNode : rootNode) {
    if (personNode instanceof ObjectNode) {
        ObjectNode object = (ObjectNode) personNode;
        object.remove("familyName");
        object.remove("middleName");
    }
}

您还可以使用Jackon的原始解析更有效地完成此操作API，但代码会更加混乱。

You could also do this more efficiently using Jackon's raw parsing API, but the code would be a lot messier.

这篇关于使用jackson删除JSON元素的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！