杰克逊反序列化具有未知的动态属性 [英] Jackson deserialization with unknown dynamic properties

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本文介绍了杰克逊反序列化具有未知的动态属性的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个JSON字符串,如:

I have a JSON string like:

"shipping_profiles": {
  "563": {
    "name": "name",
    "value": "value"            
  },
  "564": {
    "name": "name",
    "value": "value"            
  },
  "565": {
    "name": "name",
    "value": "value"            
  },
  "566": {
    "name": "name",
    "value": "value"            
  }
}

现在我用 Jackson 2.0 解析它。
我想从JSON字符串中获取列表< shipping_profiles>

是否有可能?

推荐答案

您的 shipping_profiles 属性看起来不像数组。它表示具有动态属性的对象,因此我们应该将其视为对象。如果我们对属性一无所知,我们可以使用 @JsonAnySetter 注释。算法可能如下所示:

Your shipping_profiles property doesn't look like array. It represent object with dynamic properties, so we should treat it like an object. If we do not know anything about properties we can use @JsonAnySetter annotation. Algorithm could looks like below:


  1. 将JSON反序列化为JSON模型类。

  2. 转换动态对象(使用ObjectMapper(映射)到应用程序的POJO类

  3. 随时使用应用程序的POJO。

请参阅我的示例实现。我希望,它可以帮助您解决问题。输入JSON:

Please see my example implementation. I hope, it help you solve your problem. Input JSON:

{
   "shipping_profiles":{
      "563":{
         "name":"name563",
         "value":"value563"
      },
      "564":{
         "name":"name564",
         "value":"value564"
      },
      "565":{
         "name":"name565",
         "value":"value565"
      },
      "566":{
         "name":"name566",
         "value":"value566"
      }
   }
}

示例程序:

import java.io.File;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;

import com.fasterxml.jackson.annotation.JsonAnySetter;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.databind.ObjectMapper;

public class JacksonProgram {

    public static void main(String[] args) throws IOException {
        ObjectMapper mapper = new ObjectMapper();

        File source = new File("X:/test.json");
        Entity entity = mapper.readValue(source, Entity.class);
        ShippingProfiles shippingProfiles = entity.getShippingProfiles();
        List<Map<String, String>> profileMaps = shippingProfiles.getProfiles();

        List<Profile> profiles = new ArrayList<Profile>(profileMaps.size());
        for (Map<String, String> item : profileMaps) {
            profiles.add(mapper.convertValue(item, Profile.class));
        }
        System.out.println(profiles);
    }
}

class Entity {

    @JsonProperty("shipping_profiles")
    private ShippingProfiles shippingProfiles;

    public ShippingProfiles getShippingProfiles() {
        return shippingProfiles;
    }

    public void setShippingProfiles(ShippingProfiles shippingProfiles) {
        this.shippingProfiles = shippingProfiles;
    }
}

class ShippingProfiles {

    private List<Map<String, String>> profiles = new ArrayList<Map<String, String>>();

    @JsonAnySetter
    public void setDynamicProperty(String name, Map<String, String> map) {
        profiles.add(map);
    }

    public List<Map<String, String>> getProfiles() {
        return profiles;
    }

    public void setProfiles(List<Map<String, String>> profiles) {
        this.profiles = profiles;
    }
}

class Profile {

    private String name;
    private String value;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getValue() {
        return value;
    }

    public void setValue(String value) {
        this.value = value;
    }

    @Override
    public String toString() {
        return "Profile [name=" + name + ", value=" + value + "]";
    }
}

以上应用打印:

[Profile [name=name563, value=value563], Profile [name=name564, value=value564], Profile [name=name565, value=value565], Profile [name=name566, value=value566]]

这篇关于杰克逊反序列化具有未知的动态属性的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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