使用Jersey / JAXB / Jackson的Java.util.Map到JSON对象 [英] Java.util.Map to JSON Object with Jersey / JAXB / Jackson

问题描述

我一直在尝试创建Jersey REST Web服务。我希望从Java类接收和发出JSON对象，如下所示：

I've been trying to create a Jersey REST Webservice. I want to receive and emit JSON objects from Java classes like the following:

@XmlRootElement
public class Book {

    public String code;

    public HashMap<String, String> names;

}

这应该像这样转换成JSON：

This should be converted into JSON like this:

{
    "code": "ABC123",
    "names": {
        "de": "Die fabelhafte Welt der Amelie",
        "fr": "Le fabuleux destin d'Amelie Poulain"
    }
}

但是我找不到标准的解决方案。每个人似乎都在实施他自己的包装器 解决方案。这个要求对我来说似乎是极其基本的;我无法相信这是普遍接受的解决方案，特别是因为Jersey真的是Java中最有趣的部分之一。

However I can not find a standard solution for this. Everybody seems to be implementing his own wrapper solution. This requirement seems extremly basic to me; I can't believe that this is the generally accepted solution to this, especially since Jersey is really one of the more fun parts of Java.

我也尝试过升级杰克逊1.8这只给了我这个，这是极其荒谬的JSON：

I've also tried upgrading to Jackson 1.8 which only gives me this, which is extremly obfusicated JSON:

{
    "code": "ABC123",
    "names": {
        "entry": [{
            "key": "de",
            "value": "Die fabelhafte Welt der Amelie"
        },
        {
            "key": "fr",
            "value": "Le fabuleux destin d'Amelie Poulain"
        }]
    }
}

是否有任何建议的解决方案？

Are there any proposed solutions for this?

推荐答案

我不知道为什么这不是默认设置，我花了一段时间搞清楚它，但是如果你想用Jersey进行JSON转换，添加

I don't know why this isn't the default setting, and it took me a while figuring it out, but if you want working JSON conversion with Jersey, add

    <init-param>
        <param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
        <param-value>true</param-value>
    </init-param>

到您的web.xml，所有问题都应该解决。

to your web.xml and all your problems should be solved.

PS：您还需要摆脱 @XmlRootElement 注释才能使其正常工作

PS: you also need to get rid of the @XmlRootElement annotations to make it work

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