Jax-rs json相当不错 [英] Jax-rs json pretty output

问题描述

当我使用

  @Produces（application / json）
  $ c> 

注释输出未形成人类可读形式。我如何实现这一目标？

解决方案

在项目的任何位置创建此类。它将在部署时加载。注意 .configure（SerializationConfig.Feature.INDENT_OUTPUT，true）; ，它配置映射器以格式化输出。

对于Jackson 2.0及更高版本，用以下代码替换两个 .configure（）行：
.configure（DeserializationFeature.FAIL_ON_IGNORED_PROPERTIES，false）
.configure（SerializationFeature.INDENT_OUTPUT，true）;

相应地改变你的进口。

  package com.secret; 
 
 import javax.ws.rs.Produces; 
 import javax.ws.rs.core.MediaType; 
 import javax.ws.rs.ext.ContextResolver; 
 import javax.ws.rs.ext.Provider; 
 import org.codehaus.jackson.map.DeserializationConfig; 
 import org.codehaus.jackson.map.ObjectMapper; 
 import org.codehaus.jackson.map.SerializationConfig; 
 
 / ** 
 * 
 * @author secret 
 * / 
 @Provider 
 @Produces（MediaType.APPLICATION_JSON）
公共类JacksonContextResolver实现ContextResolver< ObjectMapper> {
 private ObjectMapper objectMapper; 
 
 public JacksonContextResolver（）抛出异常{
 this.objectMapper = new ObjectMapper（）; 
 this.objectMapper 
 .configure（DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES，false）
 .configure（SerializationConfig.Feature.INDENT_OUTPUT，true）; 
} 
 
 @Override 
 public ObjectMapper getContext（Class<？> objectType）{
 return objectMapper; 
} 
} 
  

请记住格式化对性能有负面影响。

in Java when i use the

@Produces("application/json")

annotation the output is not formated into human readable form. How do i achive that?

解决方案

Create this class anywhere in your project. It will be loaded on deployment. Notice the .configure(SerializationConfig.Feature.INDENT_OUTPUT, true); which configures the mapper to format the output.

For Jackson 2.0 and later, replace the two .configure() lines with these: .configure(DeserializationFeature.FAIL_ON_IGNORED_PROPERTIES, false) .configure(SerializationFeature.INDENT_OUTPUT, true);

And change your imports accordingly.

package com.secret;

import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.ext.ContextResolver;
import javax.ws.rs.ext.Provider;
import org.codehaus.jackson.map.DeserializationConfig;
import org.codehaus.jackson.map.ObjectMapper;
import org.codehaus.jackson.map.SerializationConfig;

/**
 *
 * @author secret
 */
@Provider
@Produces(MediaType.APPLICATION_JSON)
public class JacksonContextResolver implements ContextResolver<ObjectMapper> {
    private ObjectMapper objectMapper;

    public JacksonContextResolver() throws Exception {
        this.objectMapper = new ObjectMapper();
    this.objectMapper
        .configure(DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES, false)
        .configure(SerializationConfig.Feature.INDENT_OUTPUT, true);
    }

    @Override
    public ObjectMapper getContext(Class<?> objectType) {
        return objectMapper;
    }
}

Bear in mind that formatting has a negative effect on performance.

这篇关于Jax-rs json相当不错的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！