茉莉花 - 同样方法的两个间谍 [英] Jasmine - Two spies for the same method

问题描述

我是 Jasmine 的新手，我想知道我们是否可以为同一方法创建2个间谍。这是我正在尝试的。

I'm new to Jasmine and I wanted to know if we can create 2 spies for the same method. Here is what I'm trying.

describe('something', function () {
    beforeEach(function () {
        mySpy = jasmine.createSpyObj('mySpy', 'functionInInterest');
        mySpy.functionInInterest.andCallFake(function (cb) {cb(something);});
    }

    //Some Test Cases
    describe('Here is the action!', function () {
        mySpy = jasmine.createSpyObj('mySpy', 'functionInInterest');
        mySpy.functionInInterest.andCallFake(function (cb) {cb(somethingElse);});
        //Some test cases that depends on somethingElse
    });
});

之前的测试用例这是行动！依赖于 mySpy.functionInInterest.andCallFake（function（cb）{cb（something）;}）; 作为中的测试用例，这是动作！依赖于 mySpy.functionInInterest.andCallFake（function（cb）{cb（somethingElse）;}）;

注意：两者名称相同

如何实现这一目标？提前致谢！

How can I achieve this? Thanks in advance!

推荐答案

而不是

describe('Here is the action!', function () {
        mySpy = jasmine.createSpyObj('mySpy', 'functionInInterest');
        mySpy.functionInInterest.andCallFake(function (cb) {cb(somethingElse);});
        //Some test cases that depends on somethingElse
    });

这样做

describe('Here is the action!', function () {
        mySpy_2 = jasmine.createSpyObj('mySpy', 'functionInInterest');
        mySpy_2.functionInInterest.andCallFake(function (cb) {cb(somethingElse);});
        //Some test cases that depends on somethingElse
    });

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