如何在Java中解析JSON [英] How to parse JSON in Java

问题描述

我有以下JSON文本。如何解析它以获得 pageName ， pagePic ， post_id 等等？

I have the following JSON text. How can I parse it to get pageName, pagePic, post_id, etc.?

{
   "pageInfo": {
         "pageName": "abc",
         "pagePic": "http://example.com/content.jpg"
    }
    "posts": [
         {
              "post_id": "123456789012_123456789012",
              "actor_id": "1234567890",
              "picOfPersonWhoPosted": "http://example.com/photo.jpg",
              "nameOfPersonWhoPosted": "Jane Doe",
              "message": "Sounds cool. Can't wait to see it!",
              "likesCount": "2",
              "comments": [],
              "timeOfPost": "1234567890"
         }
    ]
}

推荐答案

org.json 库易于使用。示例代码如下：

The org.json library is easy to use. Example code below:

import org.json.*;


JSONObject obj = new JSONObject(" .... ");
String pageName = obj.getJSONObject("pageInfo").getString("pageName");

JSONArray arr = obj.getJSONArray("posts");
for (int i = 0; i < arr.length(); i++)
{
    String post_id = arr.getJSONObject(i).getString("post_id");
    ......
}

您可以从以下网站找到更多示例：用Java解析JSON

You may find more examples from: Parse JSON in Java

可下载的jar： http://mvnrepository.com/artifact/org.json/json

这篇关于如何在Java中解析JSON的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！