展示Java中的协方差和逆变? [英] Demonstrate covariance and contravariance in Java?

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问题描述

请在Java中显示协方差和逆变的一个很好的例子。

Please show a good example for covariance and contravariance in Java.

推荐答案

协方差:

class Super {
  Object getSomething(){}
}
class Sub extends Super {
  String getSomething() {}
}

Sub#getSomething是协变的,因为它返回返回类型为Super#getSomething的子类(但是满足Super.getSomething()的合约)

Sub#getSomething is covariant because it returns a subclass of the return type of Super#getSomething (but fullfills the contract of Super.getSomething())

Contravariance

class Super{
  void doSomething(String parameter)
}
class Sub extends Super{
  void doSomething(Object parameter)
}

Sub#doSomething是逆变的,因为它需要Super#doSomething参数的超类参数(但是,再次填写Super#doSomething的合约)

Sub#doSomething is contravariant because it takes a parameter of a superclass of the parameter of Super#doSomething (but, again, fullfills the contract of Super#doSomething)

注意:这个例子没有在Java工作。 Java编译器会重载并且不会覆盖doSomething() - Method。其他语言确实支持这种逆转方式。

泛型

这也适用于泛型:

List<String> aList...
List<? extends Object> covariantList = aList;
List<? super String> contravariantList = aList;

您现在可以访问 covariantList的所有方法不带泛型参数(因为它必须是extends Object),但getter工作正常(因为返回的对象将始终是Object类型)

You can now access all methods of covariantList that doesn't take a generic parameter (as it must be something "extends Object"), but getters will work fine (as the returned object will always be of type "Object")

对于 contravariantList ,情况正好相反:您可以使用泛型参数访问所有方法(您知道它必须是String的超类) ,所以你总是可以传递一个),但没有getter(返回的类型可能是任何其他字符串的超类型)

The opposite is true for contravariantList: You can access all methods with generic parameters (you know it must be a superclass of "String", so you can always pass one), but no getters (The returned type may be of any other supertype of String)

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