更改Swing JTable单元格颜色 [英] Changing Swing JTable Cell Colors

问题描述

我正在尝试使用JTables，TableModels，JTableHeaders，渲染器等。我正在尝试制作一个简单的虚拟表（用于练习目的），如下所示：

I'm trying to get comfortable with JTables, TableModels, JTableHeaders, renderers, etc. I am trying to make a simple dummy table (for practice purposes) that looks like this:

-    1    2   3
A    A1   A2  A3
B    B1   B2  B3
C    C1   C2  C3

我还希望B2单元格 - 只有那个单元格 - 具有蓝色（Color.BLUE）背景 - 所有其他单元格都可以具有Swing默认颜色是自动分配的。

I also want the B2 cell - and only that cell - to have a blue (Color.BLUE) background - all other cells can have the Swing default color they are assigned automagically.

我的代码如下，基于我在本网站和互联网上找到的无数例子。但我没有得到我想要的结果。相反，我得到的表格如下：

My code is below and is based off countless examples I have found on this website and the internet at large. But I am not getting the results I want. Instead I'm getting a table that looks like this:

A    A1   A2  A3
B    B1   B2  B3
C    C1   C2  C3

请注意第一行（标题）根本不存在。另外，通过下面列出的代码，这将执行并设置所有颜色的单元格的颜色，而不仅仅是我想要的B2单元格。

Notice that the first row (the header) isn't there at all. Additionally, with the code I list below, this executes and sets the color of all the cells that color, not just the B2 cell that I want.

代码：

public class MyTable
{
    public static void main(String[] args)
    {
        String[][] data = getTableData();
        String[] cols = getTableCols();

        JFrame frame = magicallyCreateJFrame();     // I promise this works!
        MyRenderer myRenderer = new MyRenderer();   // See below

        DefaultTableModel defModel = new DefaultTableModel(data, cols);
        JTable myTable = new JTable(defModel);

        myTable.setDefaultRenderer(Object.class, myRenderer);

        frame.add(myTable);
        frame.pack();
        frame.setVisible(true);            
    }
}

public static String[] getTableCols()
{
    String cols =
    {
        "-",
        "1",
        "2",
        "3",
    };
}

public static String[][] getTableData()
{
    String[][] data =
    {
        {
            "A",
            "A1",
            "A2",
            "A3",
        },
        {
            "B",
            "B1",
            "B2",
            "B3",
        },
        {
            "C",
            "C1",
            "C2",
            "C3",
        },
    };

    return data;
}

快速肮脏的 MyRenderer class：

And the quick-n-dirty MyRenderer class:

public class MyRenderer extends DefaultTableCellRenderer  
{ 
    public Component getTableCellRendererComponent(JTable table, Object value, boolean   isSelected, boolean hasFocus, int row, int column) 
{ 
    Component c = super.getTableCellRendererComponent(table, value, isSelected, hasFocus, row, column); 

    if(row == 2 && column == 2)
        c.setBackground(new java.awt.Color(0, 0, 255)); 

    return c; 
} 

} 

除了这是可怕的代码并打破了许多最佳实践类型的模式和技术（记住这只是我正在玩的东西），我在这里做的任何东西都是明显的-obvious ？为什么我没有得到表头（第一行 - 1 2 3）？为什么我的默认单元格渲染器不能在我指定的特定B2单元格上工作？

Besides the fact that this is horrible code and breaks a lot of "best practices"-type patterns and techniques (remember this is just something I'm playing around with), is there anything I'm doing here that is glaringly-obvious? Why am I not getting a table header (first row "- 1 2 3")? Why is my default cell renderer not working on the specific B2 cell I am specifying?

JTable似乎是奇怪，美丽和强大的野兽。我正在慢慢地把我的思绪包裹在他们周围，但是我对实施感到窒息。感谢任何有用的东西！

JTables seem to be strange, beautiful and powerful beasts. I'm slowly wrapping my mind around them but am choking on the implementation. Thanks to any that can help!

推荐答案

您需要确保将渲染器重置为其默认背景颜色（并处理行）选择）：

You need to make sure you reset the renderer to its default background color (and handle row selection):

if (! table.isRowSelected(row))
{
    if(row == 2 && column == 2)
        c.setBackground(new java.awt.Color(0, 0, 255));
    else
        c.setBackground(table.getBackground());
}

将来发布正确的 SSCCE 。

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