ResultSet.getString（1）抛出java.sql.SQLException：当前光标位置的无效操作 [英] ResultSet.getString(1) throws java.sql.SQLException: Invalid operation at current cursor position

问题描述

当我运行以下servlet时：

When I run the following servlet:

// package projectcodes;
public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException {
    String UserID = request.getParameter("UserID");
    String UserPassword = request.getParameter("UserPassword");
    String userName = null;
    String Email = null;
    Encrypter encrypter = new Encrypter();
    String hashedPassword = null;
    try {
        hashedPassword = encrypter.hashPassword(UserPassword);
        Context context = new InitialContext();
        DataSource ds = (DataSource)context.lookup("java:comp/env/jdbc/photog");
        Connection connection = ds.getConnection();
        String sqlStatement = "SELECT email,firstname FROM registrationinformation WHERE password='" + hashedPassword + "'";
        PreparedStatement statement = connection.prepareStatement(sqlStatement);
        ResultSet set = statement.executeQuery();
        userName = set.getString(1);  // <<---------- Line number 28
        response.sendRedirect("portfolio_one.jsp");
        // userName = set.getString("FirstName");
        Email = set.getString(3);
        if(set.wasNull() || Email.compareTo(UserID) != 0) {
            // turn to the error page
            response.sendRedirect("LoginFailure.jsp");
        } else {
            // start the session and take to his homepage
            HttpSession session = request.getSession();
            session.setAttribute("UserName", userName);
            session.setMaxInactiveInterval(900); // If the request doesn't come withing 900 seconds the server will invalidate the session
            RequestDispatcher rd = request.getRequestDispatcher("portfolio_one.jsp");
            rd.forward(request, response); // forward to the user home-page
        }
    }catch(Exception exc) {
        System.out.println(exc);
    }

我收到以下例外情况：

INFO: java.sql.SQLException: Invalid operation at current cursor position.
at org.apache.derby.client.am.SQLExceptionFactory40.getSQLException(Unknown Source)
at org.apache.derby.client.am.SqlException.getSQLException(Unknown Source)
at org.apache.derby.client.am.ResultSet.getString(Unknown Source)
at com.sun.gjc.spi.base.ResultSetWrapper.getString(ResultSetWrapper.java:155)

-----> at projectcodes.ValidateDataForSignIn.doPost(ValidateDataForSignIn.java:28

at javax.servlet.http.HttpServlet.service(HttpServlet.java:754)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:847)
at org.apache.catalina.core.StandardWrapper.service(StandardWrapper.java:1539)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:281)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:175)
at org.apache.catalina.core.StandardPipeline.doInvoke(StandardPipeline.java:655)
at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:595)
at com.sun.enterprise.web.WebPipeline.invoke(WebPipeline.java:98)
at com.sun.enterprise.web.PESessionLockingStandardPipeline.invoke(PESessionLockingStandardPipeline.java:91)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:162)
at org.apache.catalina.connector.CoyoteAdapter.doService(CoyoteAdapter.java:330)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:231)
at com.sun.enterprise.v3.services.impl.ContainerMapper.service(ContainerMapper.java:174)
at com.sun.grizzly.http.ProcessorTask.invokeAdapter(ProcessorTask.java:828)
at com.sun.grizzly.http.ProcessorTask.doProcess(ProcessorTask.java:725)
at com.sun.grizzly.http.ProcessorTask.process(ProcessorTask.java:1019)
at com.sun.grizzly.http.DefaultProtocolFilter.execute(DefaultProtocolFilter.java:225)
at com.sun.grizzly.DefaultProtocolChain.executeProtocolFilter(DefaultProtocolChain.java:137)
at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:104)
at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:90)
at com.sun.grizzly.http.HttpProtocolChain.execute(HttpProtocolChain.java:79)
at com.sun.grizzly.ProtocolChainContextTask.doCall(ProtocolChainContextTask.java:54)
at com.sun.grizzly.SelectionKeyContextTask.call(SelectionKeyContextTask.java:59)
at com.sun.grizzly.ContextTask.run(ContextTask.java:71)
at com.sun.grizzly.util.AbstractThreadPool$Worker.doWork(AbstractThreadPool.java:532)
at com.sun.grizzly.util.AbstractThreadPool$Worker.run(AbstractThreadPool.java:513)
at java.lang.Thread.run(Thread.java:722)
    Caused by: org.apache.derby.client.am.SqlException: Invalid operation at current cursor position.
at org.apache.derby.client.am.ResultSet.checkForValidCursorPosition(Unknown Source)
at org.apache.derby.client.am.ResultSet.checkGetterPreconditions(Unknown Source)
... 30 more

服务器上面的日志显示第28行是导致异常的原因。但我无法得到例外的理由。表中的所有列都具有varchar的数据类型。

The logs above from the server show that line number 28 is the cause of the exception. But i am unable to get the reason for exception. All the columns in the table have a datatype of varchar.

我突出显示了行号28 （根据服务器日志的异常原因） in servlet代码。

I have highlighted line number 28 (cause of exception according to server logs) in the servlet code.

推荐答案

您应首先使用 next 语句。

ResultSet set = statement.executeQuery();
if (set.next()) {
    userName = set.getString(1);
    //your logic...
}

UPDATE

正如Java 6文档所说

As the Java 6 Documentation says

ResultSet游标最初位于第一行之前;对方法的第一次调用使第一行成为当前行;第二个调用使第二行成为当前行，依此类推。

A ResultSet cursor is initially positioned before the first row; the first call to the method next makes the first row the current row; the second call makes the second row the current row, and so on.

这意味着当你执行句子时

This means when you execute the sentence

ResultSet set = statement.executeQuery();

将创建ResultSet set 并指向在数据的第一个结果之前的一行。你可以这样看：

The ResultSet set will be created and pointing to a row before the first result of the data. You can look it this way:

SELECT email，firstname FROM registrationinformation

SELECT email,firstname FROM registrationinformation

    email              | firstname
    ____________________________________
0                                        <= set points to here
1   [e-mail]   | Email1 Person
2   [e-mail]        | Foo Bar

因此，在打开ResulSet后，执行方法将其移至第一行。

So, after openning your ResulSet, you execute the method next to move it to the first row.

if(set.next()) 

现在 set 看起来像这样。

    email              | firstname
    ____________________________________
0
1   [e-mail]   | Email1 Person   <= set points to here
2   [e-mail]        | Foo Bar

如果你需要读取ResultSet中的所有数据，你应该使用while而不是if：

If you need to read all the data in the ResultSet, you should use a while instead of if:

while(set.next()) {
    //read data from the actual row
    //automatically will try to forward 1 row
}

如果 set.next（）返回false，表示没有要读取的行，因此你的while循环将结束。

If the set.next() return false, it means that there was no row to read, so your while loop will end.

更多信息此处。

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