使用StringBuilder替换所有出现的String？ [英] Replace all occurrences of a String using StringBuilder?

问题描述

我是否遗漏了某些内容，或者StringBuilder是否缺少与普通String类相同的将所有出现的字符串A替换为字符串B的函数？ StringBuilder替换功能并不完全相同。有没有办法更有效地使用普通的String类生成多个字符串？

Am I missing something, or does StringBuilder lack the same "replace all occurrences of a string A with string B" function that the normal String class does? The StringBuilder replace function isn't quite the same. Is there any way to this more efficiently without generating multiple Strings using the normal String class?

推荐答案

那么，你可以写一个循环：

Well, you can write a loop:

public static void replaceAll(StringBuilder builder, String from, String to)
{
    int index = builder.indexOf(from);
    while (index != -1)
    {
        builder.replace(index, index + from.length(), to);
        index += to.length(); // Move to the end of the replacement
        index = builder.indexOf(from, index);
    }
}

请注意，在某些情况下，使用起来可能会更快 lastIndexOf ，从后面开始工作。我怀疑如果你用一个短字符串替换一个长字符串就是这种情况 - 所以当你开始时，任何替换都要少复制。无论如何，这应该给你一个起点。

Note that in some cases it may be faster to use lastIndexOf, working from the back. I suspect that's the case if you're replacing a long string with a short one - so when you get to the start, any replacements have less to copy. Anyway, this should give you a starting point.

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