Mockito：试图窥探方法是调用原始方法 [英] Mockito: Trying to spy on method is calling the original method

问题描述

我正在使用Mockito 1.9.0。我想在JUnit测试中模拟一个类的单个方法的行为，所以我有

I'm using Mockito 1.9.0. I want mock the behaviour for a single method of a class in a JUnit test, so I have

final MyClass myClassSpy = Mockito.spy(myInstance);
Mockito.when(myClassSpy.method1()).thenReturn(myResults);

问题是，在第二行， myClassSpy.method1（）实际上被调用，导致异常。我使用模拟的唯一原因是，以后，只要调用 myClassSpy.method1（），就不会调用真实方法并且 myResults 将返回对象。

The problem is, in the second line, myClassSpy.method1() is actually getting called, resulting in an exception. The only reason I'm using mocks is so that later, whenever myClassSpy.method1() is called, the real method won't be called and the myResults object will be returned.

MyClass 是一个接口， myInstance 是一个实现如果这很重要。

MyClass is an interface and myInstance is an implementation of that, if that matters.

我需要做些什么才能纠正这种间谍行为？

What do I need to do to correct this spying behaviour?

推荐答案

让我引用官方文档：

关于监视真实对象的重要问题！

有时无法使用（对象）咒语间谍。示例：

Important gotcha on spying real objects!

Sometimes it's impossible to use when(Object) for stubbing spies. Example:

List list = new LinkedList();
List spy = spy(list);

// Impossible: real method is called so spy.get(0) throws IndexOutOfBoundsException (the list is yet empty)
when(spy.get(0)).thenReturn("foo");

// You have to use doReturn() for stubbing
doReturn("foo").when(spy).get(0);

在您的情况下，它类似于：

In your case it goes something like:

doReturn(resulstIWant).when(myClassSpy).method1();

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