最有效的ResultSet转换为JSON？ [英] Most efficient conversion of ResultSet to JSON?

问题描述

以下代码使用 ResultSet 转换为JSON字符串。 html> JSONArray 和 JSONObject 。

The following code converts a ResultSet to a JSON string using JSONArray and JSONObject.

import org.json.JSONArray;
import org.json.JSONObject;
import org.json.JSONException;

import java.sql.SQLException;
import java.sql.ResultSet;
import java.sql.ResultSetMetaData;

public class ResultSetConverter {
  public static JSONArray convert( ResultSet rs )
    throws SQLException, JSONException
  {
    JSONArray json = new JSONArray();
    ResultSetMetaData rsmd = rs.getMetaData();

    while(rs.next()) {
      int numColumns = rsmd.getColumnCount();
      JSONObject obj = new JSONObject();

      for (int i=1; i<numColumns+1; i++) {
        String column_name = rsmd.getColumnName(i);

        if(rsmd.getColumnType(i)==java.sql.Types.ARRAY){
         obj.put(column_name, rs.getArray(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.BIGINT){
         obj.put(column_name, rs.getInt(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.BOOLEAN){
         obj.put(column_name, rs.getBoolean(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.BLOB){
         obj.put(column_name, rs.getBlob(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.DOUBLE){
         obj.put(column_name, rs.getDouble(column_name)); 
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.FLOAT){
         obj.put(column_name, rs.getFloat(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.INTEGER){
         obj.put(column_name, rs.getInt(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.NVARCHAR){
         obj.put(column_name, rs.getNString(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.VARCHAR){
         obj.put(column_name, rs.getString(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.TINYINT){
         obj.put(column_name, rs.getInt(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.SMALLINT){
         obj.put(column_name, rs.getInt(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.DATE){
         obj.put(column_name, rs.getDate(column_name));
        }
        else if(rsmd.getColumnType(i)==java.sql.Types.TIMESTAMP){
        obj.put(column_name, rs.getTimestamp(column_name));   
        }
        else{
         obj.put(column_name, rs.getObject(column_name));
        }
      }

      json.put(obj);
    }

    return json;
  }
}

• 是否有更快的速度方式？


• 有没有一种使用更少内存的方法？



推荐答案

JIT编译器可能会非常快，因为它只是分支和基本测试。你可以通过HashMap查找回调来使它更优雅，但我怀疑它会更快。至于记忆，这是非常苗条的。

The JIT Compiler is probably going to make this pretty fast since it's just branches and basic tests. You could probably make it more elegant with a HashMap lookup to a callback but I doubt it would be any faster. As to memory, this is pretty slim as is.

不知何故，我怀疑这段代码实际上是内存或性能的关键瓶颈。你有什么理由尝试优化它吗？

Somehow I doubt this code is actually a critical bottle neck for memory or performance. Do you have any real reason to try to optimize it?

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