如何从字符串中加载XML中的org.w3c.dom.Document？ [英] How do I load an org.w3c.dom.Document from XML in a string?

问题描述

我在字符串中有一个完整的XML文档，并且想要一个 Document 对象。谷歌出现了各种各样的垃圾。什么是最简单的解决方案？ （在Java 1.5中）

I have a complete XML document in a string and would like a Document object. Google turns up all sorts of garbage. What is the simplest solution? (In Java 1.5)

解决方案感谢 Matt McMinn ，我已经确定了这个实现。它具有适当级别的输入灵活性和异常粒度。 （很高兴知道错误是来自格式错误的XML - SAXException - 或者只是错误的IO - IOException 。）

Solution Thanks to Matt McMinn, I have settled on this implementation. It has the right level of input flexibility and exception granularity for me. (It's good to know if the error came from malformed XML - SAXException - or just bad IO - IOException.)

public static org.w3c.dom.Document loadXMLFrom(String xml)
    throws org.xml.sax.SAXException, java.io.IOException {
    return loadXMLFrom(new java.io.ByteArrayInputStream(xml.getBytes()));
}

public static org.w3c.dom.Document loadXMLFrom(java.io.InputStream is) 
    throws org.xml.sax.SAXException, java.io.IOException {
    javax.xml.parsers.DocumentBuilderFactory factory =
        javax.xml.parsers.DocumentBuilderFactory.newInstance();
    factory.setNamespaceAware(true);
    javax.xml.parsers.DocumentBuilder builder = null;
    try {
        builder = factory.newDocumentBuilder();
    }
    catch (javax.xml.parsers.ParserConfigurationException ex) {
    }  
    org.w3c.dom.Document doc = builder.parse(is);
    is.close();
    return doc;
}

推荐答案

这适用于Java 1.5 - 为了便于阅读，我删除了特定的例外情况。

This works for me in Java 1.5 - I stripped out specific exceptions for readability.

import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import java.io.ByteArrayInputStream;

public Document loadXMLFromString(String xml) throws Exception
{
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();

    factory.setNamespaceAware(true);
    DocumentBuilder builder = factory.newDocumentBuilder();

    return builder.parse(new ByteArrayInputStream(xml.getBytes()));
}

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