在每个第n个位置拆分一个字符串 [英] Split a string, at every nth position

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问题描述

我使用这个正则表达式在每个第三个位置分割一个字符串:

I use this regex to split a string at every say 3rd position:

String []thisCombo2 = thisCombo.split("(?<=\\G...)");

其中G后面的3个点表示要分割的每个第n个位置。在这种情况下,3个点表示每3个位置。例如:

where the 3 dots after the G indicates every nth position to split. In this case, the 3 dots indicate every 3 positions. An example:

Input: String st = "123124125134135145234235245"
Output: 123 124 125 134 135 145 234 235 245.

我的问题是,如何让用户控制字符串必须的位置数量分裂?换句话说,如何制作用户控制的3个点,n个点?

My question is, how do i let the user control the number of positions where the string must be split at? In other words, how do I make those 3 dots, n dots controlled by the user?

推荐答案

为了提高性能,另一种方法是在循环中使用 substring()

For a big performance improvement, an alternative would be to use substring() in a loop:

public String[] splitStringEvery(String s, int interval) {
    int arrayLength = (int) Math.ceil(((s.length() / (double)interval)));
    String[] result = new String[arrayLength];

    int j = 0;
    int lastIndex = result.length - 1;
    for (int i = 0; i < lastIndex; i++) {
        result[i] = s.substring(j, j + interval);
        j += interval;
    } //Add the last bit
    result[lastIndex] = s.substring(j);

    return result;
}

示例:

Input:  String st = "1231241251341351452342352456"
Output: 123 124 125 134 135 145 234 235 245 6.

它不像 stevevls'解决方案那么短,但它是<强大>方式更有效(见下文)我认为将来更容易调整,当然取决于您的情况。

It's not as short as stevevls' solution, but it's way more efficient (see below) and I think it would be easier to adjust in the future, of course depending on your situation.

2,000 字符长字符串 - 间隔 3

2,000 characters long string - interval is 3.

split((?< = \\\\。{+ count +}))性能(以毫秒为单位):

split("(?<=\\G.{" + count + "})") performance (in miliseconds):

7, 7, 5, 5, 4, 3, 3, 2, 2, 2

splitStringEvery() substring())性能(以毫秒为单位):

splitStringEvery() (substring()) performance (in miliseconds):

2, 0, 0, 0, 0, 1, 0, 1, 0, 0






2,000,000 字符长字符串 - 间隔 3


2,000,000 characters long string - interval is 3.

split()性能(以毫秒为单位):

split() performance (in miliseconds):

207, 95, 376, 87, 97, 83, 83, 82, 81, 83

splitStringEvery()性能(以毫秒为单位):

splitStringEvery() performance (in miliseconds):

44, 20, 13, 24, 13, 26, 12, 38, 12, 13






2,000,000 字符长字符串 - 间隔 30


2,000,000 characters long string - interval is 30.

split()性能(以毫秒为单位):

split() performance (in miliseconds):

103, 61, 41, 55, 43, 44, 49, 47, 47, 45

splitStringEvery()性能(以毫秒为单位):

splitStringEvery() performance (in miliseconds):

7, 7, 2, 5, 1, 3, 4, 4, 2, 1






结论:

splitStringEvery()方法快得多(即使在 Java 7u6中的更改),并且当间隔变得更高时升级

The splitStringEvery() method is a lot faster (even after the changes in Java 7u6), and it escalates when the intervals become higher.

即用型测试代码:

pastebin.com/QMPgLbG9

这篇关于在每个第n个位置拆分一个字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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