无法创建JAXBContext创建我的wsdl [英] Unable to create JAXBContext creating my wsdl
问题描述
我正在尝试为webservices生成我的WSDL,但是我收到此错误:
I am trying to generate my WSDL for webservices but I get this error:
Note: ap round: 2
Exception in thread "main" javax.xml.ws.WebServiceException: Unable to create JAXBContext
at com.sun.xml.internal.ws.model.AbstractSEIModelImpl.createJAXBContext(AbstractSEIModelImpl.java:153)
at com.sun.xml.internal.ws.model.AbstractSEIModelImpl.postProcess(AbstractSEIModelImpl.java:83)
at com.sun.xml.internal.ws.model.RuntimeModeler.buildRuntimeModel(RuntimeModeler.java:244)
at com.sun.tools.internal.ws.wscompile.WsgenTool.buildModel(WsgenTool.java:229)
at com.sun.tools.internal.ws.wscompile.WsgenTool.run(WsgenTool.java:112)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at com.sun.tools.internal.ws.Invoker.invoke(Invoker.java:105)
at com.sun.tools.internal.ws.WsGen.main(WsGen.java:41)
Caused by: java.security.PrivilegedActionException: com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException: 1 counts of IllegalAnnotationExceptions
java.lang.StackTraceElement does not have a no-arg default constructor.
this problem is related to the following location:
at java.lang.StackTraceElement
at public java.lang.StackTraceElement[] java.lang.Throwable.getStackTrace()
at java.lang.Throwable
at java.lang.Exception
at java.sql.SQLException
at private java.sql.SQLException wsdb.jaxws.SQLExceptionBean.nextException
at wsdb.jaxws.SQLExceptionBean
at java.security.AccessController.doPrivileged(Native Method)
at com.sun.xml.internal.ws.model.AbstractSEIModelImpl.createJAXBContext(AbstractSEIModelImpl.java:140)
... 10 more
Caused by: com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException: 1 counts of IllegalAnnotationExceptions
java.lang.StackTraceElement does not have a no-arg default constructor.
this problem is related to the following location:
at java.lang.StackTraceElement
at public java.lang.StackTraceElement[] java.lang.Throwable.getStackTrace()
at java.lang.Throwable
at java.lang.Exception
at java.sql.SQLException
at private java.sql.SQLException wsdb.jaxws.SQLExceptionBean.nextException
at wsdb.jaxws.SQLExceptionBean
at com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException$Builder.check(IllegalAnnotationsException.java:91)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.getTypeInfoSet(JAXBContextImpl.java:436)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl.(JAXBContextImpl.java:277)
at com.sun.xml.internal.bind.v2.runtime.JAXBContextImpl$JAXBContextBuilder.build(JAXBContextImpl.java:1100)
at com.sun.xml.internal.bind.v2.ContextFactory.createContext(ContextFactory.java:143)
at com.sun.xml.internal.bind.api.JAXBRIContext.newInstance(JAXBRIContext.java:95)
at com.sun.xml.internal.ws.developer.JAXBContextFactory$1.createJAXBContext(JAXBContextFactory.java:97)
at com.sun.xml.internal.ws.model.AbstractSEIModelImpl$1.run(AbstractSEIModelImpl.java:148)
at com.sun.xml.internal.ws.model.AbstractSEIModelImpl$1.run(AbstractSEIModelImpl.java:140)
... 12 more
我在网上看到了一些关于这个开头的讨论,为所有类构建一个构造函数,直到创建另一个xml规范。事实上,没有一个真正的答案,或者我测试的解决方案没有任何效果。
I saw a few discusion in internet about this begin with build a constructor for all classes until create another xml specification. The truth is there is no a real answer for this or the solutions that I test doesnt work any.
我在这里读到了关于这个问题的讨论,但它没有终结,我不知道如何解决。如果有人对此有所了解,我很感激为了避免这种情况加入我的方向。
I read a discussion here about this problem but it was unterminated and I dont know how to resolve. If somebody has a cluee about this I so appreciated to addrees me into rigth direction to avoid this.
我正在使用Debian Squezze,Java 1.6_20,JAX-WS JAX- JDK 6中的WS RI 2.1.6和wsgen生成wsdl。它做的第一步是正确的,用bean类生成jaxws目录。
I am using Debian Squezze, Java 1.6_20, JAX-WS JAX-WS RI 2.1.6 in JDK 6 and wsgen to generate the wsdl. The first step it did correct, generate the jaxws directory with bean classes.
推荐答案
Throwable
对象(即异常和错误)无法直接传输,因为它们无法序列化为XML( StackTraceElement
没有no -arg构造函数,这是JAXB所必需的。
Throwable
objects (that means exceptions and errors) can't be transferred directly, because they can't be serialized to XML (the StackTraceElement
doesn't have a no-arg constructor, which is required by JAXB).
您必须使用SOAP错误。请参阅此问题。它指向您应该放在异常类上的 @WebFault
注释。 (也可能检查这个和这个)
You have to use SOAP faults for that. See this question. It points you to the @WebFault
annotation which you should put on your exception class. (Also probably check this and this)
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