java正则表达式unclosed字符类 [英] java regex pattern unclosed character class

问题描述

我需要一些帮助。我得到：

I need some help. Im getting:

Caused by: java.util.regex.PatternSyntaxException: Unclosed character class near index 24
^[a-zA-Z└- 0-9£µ /.'-\]*$
                        ^
        at java.util.regex.Pattern.error(Pattern.java:1713)
        at java.util.regex.Pattern.clazz(Pattern.java:2254)
        at java.util.regex.Pattern.sequence(Pattern.java:1818)
        at java.util.regex.Pattern.expr(Pattern.java:1752)
        at java.util.regex.Pattern.compile(Pattern.java:1460)
        at java.util.regex.Pattern.<init>(Pattern.java:1133)
        at java.util.regex.Pattern.compile(Pattern.java:823)

这是我的代码：

String testString = value.toString();

Pattern pattern = Pattern.compile("^[a-zA-Z\300-\3770-9\u0153\346 \u002F.'-\\]*$");
Matcher m = pattern.matcher(testString);

我必须使用unicode值，因为我正在使用xhtml。

I have to use the unicode value for some because I'm working with xhtml.

任何帮助都会很棒！

推荐答案

假设您要匹配 \ 和 - 而不是] ：

Assuming that you want to match \ and - and not ]:

Pattern pattern = Pattern.compile("^[a-zA-Z\300-\3770-9\u0153\346 \u002F.'\\\\-]*$");

你需要双倍逃避反斜杠，如 \ 也是正则表达式中的转义字符。因此 \\] 转义java的反斜杠，但不转义正则表达式。你需要添加另一个java-escaped \ ，以便regex-escape你的第二个java-escaped \ 。

You need to double escape your backslashes, as \ is also an escape character in regex. Thus \\] escapes the backslash for java but not for regex. You need to add another java-escaped \ in order to regex-escape your second java-escaped \.

所以 \\\\ 在java转义成为 \\\之后\\ 然后正则表达式转义为 \ 。

So \\\\ after java escaping becomes \\ which is then regex escaped to \.

移动 - 到序列的末尾意味着它被用作一个字符，而不是Pshemo指出的范围运算符。

Moving - to the end of the sequence means that it is used as a character, instead of a range operator as pointed out by Pshemo.

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