命令行参数的问题，其中包含空格 [英] Issue with Command Line arguments which got spaces in it

问题描述

我遇到了一个奇怪的问题，经过大量的调试，我找到了理由的原因。
我有一个Java程序，我通过bash脚本在Linux环境中执行。

I was struck in a weird problem , for which i found out the cause of reason , after lot of debugging . I have a Java program which i am executing in Linux environment through a bash script .

这是我的简单bash脚本，它接受一个String。

This is my simple bash script , which accepts a String .

#!/bin/bash
java -cp  com.QuoteTester $1

问题是命令行参数可以是Spaces还是没有空格。
例如它可以是

The issue is that the command line argument can be with Spaces or Without spaces . For example it can be either

Apple Inc. 2013 Jul 05 395.00 Call   

OR

Apple

根据我的代码，就是这样

As per my code it is this way

public static void main(String[] args) 
{
String symbol = args[0];

if (symbol.trim().contains(" ")) // Option
{

}

else  // Stock 
{

}

所以问题是，当我试图以这种方式执行时

So the issue is that , when i am trying to execute it this way

./ quotetester Apple Inc. 2013年7月05日395.00致电

它唯一总是转到 else条件即股票。

its only always going to the else condition that is Stock .

无论如何我可以解决这个问题吗？

Is there anyway i can resolve this ??

推荐答案

当你传递带空格的命令行参数时，它们被视为空格分隔的参数，并且是分裂在太空上。所以，你实际上没有一个参数，而是多个参数。

When you pass command line arguments with spaces, they are taken as space separated arguments, and are splitted on space. So, you don't actually have a single argument, but multiple arguments.

如果你想用空格传递参数，请使用引号：

If you want to pass arguments with spaces, use quotes:

java classname "Apple Inc. 2013 Jul 05 395.00 Call"

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