使用.next（）或.nextLine（）的java字符串变量 [英] java string variable using .next() or .nextLine()

问题描述

以下是我的源代码：

package functiontest;

import java.io.BufferedWriter;
import java.io.File;
import java.io.FileWriter;
import java.io.IOException;
import java.util.Scanner;

public class FunctionTest {

public static void main(String[] args) {
     Scanner scan = new Scanner(System.in);
    int option;
    String cname, cpassword="testpassword",chp="010-000000";

//        cname="clerk test";

    System.out.println("1. add");
    System.out.println("2. delete");
    option = scan.nextInt();
    switch(option)
    {
        case 1:
            System.out.print("Enter clerk name:\t");
            cname = scan.nextLine();
            File cfile = new File("clerk/"+cname+".txt");
               FileWriter cwrite;
               try
               {
                   cwrite = new FileWriter(cfile);
                   BufferedWriter cbuf = new BufferedWriter(cwrite);
                   cbuf.write("clerk name:\t" +cname);
                   cbuf.write("clerk password:\t"+cpassword);
                   cbuf.write("clerk handphone number:\t"+chp);
                   cbuf.flush();
                   cbuf.close();
                   System.out.println("The clerk profile create completely");
               }catch(IOException e)
               {
                   System.out.println("Error! clerk profile cannot create");
               }
            ;break;
        case 2:
            String dclerk;
//                dclerk = "clerk test";
                System.out.print("\nPlease enter clerk name for delete:\t");
                dclerk = scan.next();
                File dcfile = new File("clerk/"+dclerk+".txt");
                if(!dcfile.exists()) 
                {
                    System.out.println("Error! the clerk profile not exist");
                }
                try
                {
                    dcfile.delete();
                    System.out.println(dclerk + "'s prifle successful delete");
                }catch(Exception e)
                {
                    System.out.println("Something wrong! " + dclerk +" profile cannot delete");
                    };break;
        }
    }
}

我无法输入变量name cname

i cannot the enter the variable name cname

        cname = scan.nextLine()

当我运行程序时，它显示如下结果：

when i run the program it show the result as below:

run:
1. add
2. delete
1
Enter clerk name:   The clerk profile create completely

当我使用 .next（）时：

cname = scan.next()

它无法读取

cname

带空格，示例

clerk test 

它会读取

clerk 

我该怎么做？

推荐答案

你的问题是该行

option = scan.nextInt();

在整数后不读取新行字符。因此，当您稍后执行 nextLine（）时，最终会读取新行。

does not read the new line character after the integer. So that new line is finally read when you do nextLine(), later on.

要解决此问题，您应该添加额外的

To fix this, you should add an extra

scan.nextLine()

调用 nextInt（），然后使用

cname = scan.nextLine();

当你想要阅读职员的名字时。

when you want to read the clerk's name.

这篇关于使用.next（）或.nextLine（）的java字符串变量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！