试图共享的图像 [英] Trying to share the image
问题描述
我有图像阵列，它们被显示在图像视图。我想分享我想从其中任何图像。我已经写了code，但它也有一些问题。出现的弹出窗口，但图像不能共享，它说无法加载图像。
下面是我的code：
私人无效shareImage（）{
意图sharingIntent =新的意图（Intent.ACTION_SEND）;
乌里screenshotUri = Uri.parse（（拇指[J]））;
尝试 {
InputStream的流= getContentResolver（）。openInputStream（
screenshotUri）;
}赶上（FileNotFoundException异常E）{
// TODO自动生成的catch块
e.printStackTrace（）;
}
sharingIntent.setType（为image / jpeg）;
sharingIntent.putExtra（Intent.EXTRA_STREAM，screenshotUri）;
startActivity（Intent.createChooser（sharingIntent，分享图像使用））;
}
和我初始化这个 shareImage（）在我onClickListener。
拇指是我的字符串数组。
我究竟做错了什么？
修改
私有String []拇指=新的String [] {
http://i1040.photobucket.com/albums/b406/Aleem_Ahmed/seven-min_zpsdnohn4io.png
http://i1040.photobucket.com/albums/b406/Aleem_Ahmed/one-min_zpsxdzul6kt.png};
您不能直接共享远程图像。份额之前的图像需要下载它在该装置的本地存储。为了下载图片最简单的方法是的AsyncTask 。
这是一个快速验证的概念，你可以看到图像被下载到缓存目录，之后分享：
公共类SampleActivity延伸活动{
@覆盖
保护无效的onCreate（包savedInstanceState）{
super.onCreate（savedInstanceState）;
的setContentView（R.layout.activity_sample）;
findViewById（android.R.id.button1）.setOnClickListener（新View.OnClickListener（）{
@覆盖
公共无效的onClick（视图查看）{
新ShareImageTask（）执行（http://s.imgur.com/images/logo-1200-630.jpg）;
}
}）;
}
私有类ShareImageTask扩展的AsyncTask＆LT;字符串，太虚，字符串＆GT; {
@覆盖
保护字符串doInBackground（字符串...网址）{
字符串URL =网址[0];
字符串路径= NULL;
尝试 {
的InputStream的InputStream =新的java.net.URL（URL）.openStream（）;
点阵位图= BitmapFactory.de codeStream（InputStream的）;
文件outputDir = getExternalCacheDir（）; //上下文作为活动的指针
文件OUTPUTFILE = File.createTempFile（share_image，巴纽，outputDir）;
FileOutputStream中FOS =新的FileOutputStream（OUTPUTFILE）;
bitmap.com preSS（Bitmap.Com pressFormat.PNG，100，FOS）;
fos.close（）;
PATH = outputFile.getPath（）;
}赶上（例外五）{
e.printStackTrace（）;
PATH = NULL;
}
返回路径;
}
保护无效onPostExecute（字符串结果）{
如果（TextUtils.isEmpty（结果））{
Toast.makeText（SampleActivity.this，发生错误，Toast.LENGTH_LONG）.show（）;
返回;
}
份额（结果）;
}
}
私人无效份额（字符串路径）{
档案文件=新的文件（路径）;
意图sharingIntent =新的意图（Intent.ACTION_SEND）;
sharingIntent.setType（图像/ *）;
sharingIntent.putExtra（Intent.EXTRA_STREAM，Uri.fromFile（文件））;
startActivity（Intent.createChooser（sharingIntent，分享图像使用））;
}
}
不要忘了添加这两个权限你的的AndroidManifest.xml
＆LT;使用-权限的Android：名称=android.permission.INTERNET对/＆GT;
＆LT;使用-权限的Android：名称=android.permission.WRITE_EXTERNAL_STORAGE/＆GT;
例如在code，你可以改变你的 shareImage 的方法如下：
私人无效shareImage（）{
新ShareImageTask（）执行（拇指[J]）;
}
I have an array of images, they are being displayed in an image view. I want to share any image i want out of them. I have written a code but it has some problem. The popup window appears but the image cannot be shared, it says failed to load image.
Here is my code:
private void shareImage() {
Intent sharingIntent = new Intent(Intent.ACTION_SEND);
Uri screenshotUri = Uri.parse((thumb[j]));
try {
InputStream stream = getContentResolver().openInputStream(
screenshotUri);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
sharingIntent.setType("image/jpeg");
sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
startActivity(Intent.createChooser(sharingIntent, "Share image using"));
}
And i am initializing this shareImage() in my onClickListener.
thumb is my string array.
What am i doing wrong?
EDIT
private String[] thumb = new String[] {
"http://i1040.photobucket.com/albums/b406/Aleem_Ahmed/seven-min_zpsdnohn4io.png",
"http://i1040.photobucket.com/albums/b406/Aleem_Ahmed/one-min_zpsxdzul6kt.png" };
You can't directly share a remote image. Before share the image you need to download it in the local storage of the device. To download the image the simplest method is the AsyncTask.
This is a fast proof-of-concept, as you can see the image is downloaded in the cache directory and after that shared:
public class SampleActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_sample);
findViewById(android.R.id.button1).setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
new ShareImageTask().execute("http://s.imgur.com/images/logo-1200-630.jpg");
}
});
}
private class ShareImageTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... urls) {
String url = urls[0];
String path = null;
try {
InputStream inputStream = new java.net.URL(url).openStream();
Bitmap bitmap = BitmapFactory.decodeStream(inputStream);
File outputDir = getExternalCacheDir(); // context being the Activity pointer
File outputFile = File.createTempFile("share_image", ".png", outputDir);
FileOutputStream fos = new FileOutputStream(outputFile);
bitmap.compress(Bitmap.CompressFormat.PNG, 100, fos);
fos.close();
path = outputFile.getPath();
} catch (Exception e) {
e.printStackTrace();
path = null;
}
return path;
}
protected void onPostExecute(String result) {
if (TextUtils.isEmpty(result)) {
Toast.makeText(SampleActivity.this, "Error occurred", Toast.LENGTH_LONG).show();
return;
}
share(result);
}
}
private void share(String path) {
File file = new File(path);
Intent sharingIntent = new Intent(Intent.ACTION_SEND);
sharingIntent.setType("image/*");
sharingIntent.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(file));
startActivity(Intent.createChooser(sharingIntent, "Share image using"));
}
}
Don't forget to add these two permission to your AndroidManifest.xml
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />
For example in your code you can change your shareImage method to this:
private void shareImage() {
new ShareImageTask().execute(thumb[j]);
}
这篇关于试图共享的图像的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
