如何使用JAXB在Java中解析此XML？ [英] How do I parse this XML in Java with JAXB?

问题描述

我有以下XML，没有XSD或者我想使用JAXB解析为java对象的模式，因为我听说它比SAX更好。有没有办法用注释或更好的方法来实现这一点？这样做是为了让我只需要一个FosterHome课程吗？我很难找到如何做到这一点任何帮助都很感激。

I have the following XML, no XSD or schema with it that I want to parse to java object(s) using JAXB as I heard its better than SAX. Is there a way to accomplish this with annotations or a better way to do this? Does it make it so that i just need a single FosterHome class? I am having trouble finding how to do this any help is grateful.

我原本想要有一个FosterHome，Family和Child课程。使用JAXB，不再需要3个类？我不知道如何解决这个问题，因为ChildID出现在两个不同的领域。

I was originally thinking of having a FosterHome, Family, and Child class. Using JAXB, is having 3 classes no longer necessary? Im not sure how to deal with this as ChildID shows up in two different areas.

<?xml version="1.0" encoding="UTF-8"?>
<FosterHome>
    <Orphanage>Happy Days Daycare</Orphanage>
    <Location>Apple Street</Location>
    <Families>
        <Family>
            <ParentID>Adams</ParentID>
            <ChildList>
                <ChildID>Child1</ChildID>
                <ChildID>Child2</ChildID>
            </ChildList>
        </Family>
        <Family>
            <ParentID>Adams</ParentID>
            <ChildList>
                <ChildID>Child3</ChildID>
                <ChildID>Child4</ChildID>
            </ChildList>
        </Family>
    </Families>
    <RemainingChildList>
        <ChildID>Child5</ChildID>
        <ChildID>Child6</ChildID>
    </RemainingChildList>
</FosterHome>

推荐答案

您可以执行以下操作。通过利用 @XmlElementWrapper ，您可以减少所需的课程数量：

You could do the following. By leveraging @XmlElementWrapper you can reduce the amount of classes that you require:

FosterHome

package nov18;

import java.util.List;
import javax.xml.bind.annotation.*;

@XmlRootElement(name="FosterHome")
@XmlAccessorType(XmlAccessType.FIELD)
public class FosterHome {

    @XmlElement(name="Orphanage")
    private String orphanage;

    @XmlElement(name="Location")
    private String location;

    @XmlElementWrapper(name="Families")
    @XmlElement(name="Family")
    private List<Family> families;

    @XmlElementWrapper(name="RemainingChildList")
    @XmlElement(name="ChildID")
    private List<String> remainingChildren;

}

家庭

package nov18;

import java.util.List;   
import javax.xml.bind.annotation.*;

@XmlAccessorType(XmlAccessType.FIELD)
public class Family {

    @XmlElement(name="ParentID")
    private String parentID;

    @XmlElementWrapper(name="ChildList")
    @XmlElement(name="ChildID")
    private List<String> childList;

}

演示

package nov18;

import java.io.File;
import javax.xml.bind.*;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(FosterHome.class);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        FosterHome fosterHome = (FosterHome) unmarshaller.unmarshal(new File("src/nov18/input.xml"));

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(fosterHome, System.out);
    }

}

输入/输出

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<FosterHome>
    <Orphanage>Happy Days Daycare</Orphanage>
    <Location>Apple Street</Location>
    <Families>
        <Family>
            <ParentID>Adams</ParentID>
            <ChildList>
                <ChildID>Child1</ChildID>
                <ChildID>Child2</ChildID>
            </ChildList>
        </Family>
        <Family>
            <ParentID>Adams</ParentID>
            <ChildList>
                <ChildID>Child3</ChildID>
                <ChildID>Child4</ChildID>
            </ChildList>
        </Family>
    </Families>
    <RemainingChildList>
        <ChildID>Child5</ChildID>
        <ChildID>Child6</ChildID>
    </RemainingChildList>
</FosterHome>

更多信息

• http://blog.bdoughan.com/2010 /09/jaxb-collection-properties.html

• http://blog.bdoughan.com/2010/09/jaxb-collection-properties.html

UPDATE

我可以轻松地迭代/打印
系列中的所有ChildID class？

Is there I easy way I can iterate/print out all the ChildID in the Family class?

您可以执行以下操作：

    for(Family family : fosterHome.getFamilies()) {
        System.out.println(family.getParentID());
        for(String childID : family.getChildList()) {
            System.out.println("    " + childID);
        }
    }

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