如何为每个hashmap? [英] How to for each the hashmap?
本文介绍了如何为每个hashmap?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有这个字段:
HashMap<String, HashMap> selects = new HashMap<String, HashMap>();
对于每个 Hash< String,HashMap>
我需要创建一个 ComboBox
,其项目是 HashMap< String,** HashMap *的值(恰好是HashMap本身) *>
。
For each Hash<String, HashMap>
I need to create a ComboBox
, whose items are the value (which happens to be a HashMap itself) of HashMap <String, **HashMap**>
.
通过(无效)演示:
for (int i=0; i < selects.size(); i++) {
HashMap h = selects[i].getValue();
ComboBox cb = new ComboBox();
for (int y=0; y < h.size(); i++) {
cb.items.add(h[y].getValue);
}
}
推荐答案
我知道我有点迟到了,但是我会分享我做的事情,以防它帮助其他人:
I know I'm a bit late for that one, but I'll share what I did too, in case it helps someone else :
HashMap<String, HashMap> selects = new HashMap<String, HashMap>();
for(Map.Entry<String, HashMap> entry : selects.entrySet()) {
String key = entry.getKey();
HashMap value = entry.getValue();
// do what you have to do here
// In your case, another loop.
}
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