列出.zip目录而不提取 [英] List .zip directories without extracting

问题描述

我正在使用Java构建文件资源管理器，我正在列出JTree中的文件/文件夹。我现在要做的是当我到达一个压缩文件夹时，我想列出其内容，但不先将其解压缩。

I am building a file explorer in Java and I am listing the files/folders in JTrees. What I am trying to do now is when I get to a zipped folder I want to list its contents, but without extracting it first.

如果有人有想法，请分享。

If anyone has an idea, please share.

推荐答案

我建议你看看 ZipFile.entries（） 。

I suggest you have a look at ZipFile.entries().

以下是一些代码：

try (ZipFile zipFile = new ZipFile("test.zip")) {
    Enumeration zipEntries = zipFile.entries();
    while (zipEntries.hasMoreElements()) {
        String fileName = ((ZipEntry) zipEntries.nextElement()).getName();
        System.out.println(fileName);
    }
}

如果您使用的是 Java 8 ，您可以使用 ZipFile :: stream 避免使用几乎已弃用的 Enumeration 类，如下所示：

If you're using Java 8, you can avoid the use of the almost deprecated Enumeration class using ZipFile::stream as follows:

zipFile.stream()
       .map(ZipEntry::getName)
       .forEach(System.out::println);

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如果您需要知道某个条目是否是目录与否，你可以使用 ZipEntry.isDirectory 。除了没有提取文件之外，你得到的信息不多（出于显而易见的原因）。

---

If you need to know whether an entry is a directory or not, you could use ZipEntry.isDirectory. You can't get much more information than than without extracting the file (for obvious reasons).

如果你想要避免提取所有文件，您可以使用 ZipFile.getInputStream 对于每个 ZipEntry 。 （请注意，您不需要将解压缩的数据存储在磁盘上，您可以随时读取输入流并丢弃字节。

If you want to avoid extracting all files, you can extract one file at a time using ZipFile.getInputStream for each ZipEntry. (Note that you don't need to store the unpacked data on disk, you can just read the input stream and discard the bytes as you go.

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