JAX-RS jersey ExceptionMappers用户定义的异常 [英] JAX-RS jersey ExceptionMappers User-Defined Exception

问题描述

我是新手，试图阅读一些文档，但它不起作用，请耐心等待。

I am new to this, trying to achieve reading some docs but its not working, please bear with me.

我创建了一个 UserNotFoundMapper 使用 ExceptionMappers ，如下所示：

I have created a UserNotFoundMapper using ExceptionMappers like this:

public class UserNotFoundMapper implements ExceptionMapper<UserNotFoundException> {

@Override
public Response toResponse(UserNotFoundException ex) {
    return Response.status(404).entity(ex.getMessage()).type("text/plain").build();
}

}

这在我的服务中：

@GET
@Path("/user")
public Response getUser(@QueryParam("id") String id) throws UserNotFoundException{
    //Some user validation code with DB hit, if not found then
    throw new UserNotFoundException();
}

UserNotFoundException 是用户定义的例外。

我试过这个：

public class UserNotFoundException extends Exception {
       //SOME block of code 
}

但是当我调用该服务时未调用 UserDefinedExceptionMapper 。似乎我可能会遗漏 UserDefinedException 中的内容。那么如何定义这个例外呢？

But when I invoke the service, the UserDefinedExceptionMapper is not getting invoked. It seems I might be missing something in the UserDefinedException. How to define this exception then?

请告诉我如何定义 UserNotFoundException 。

推荐答案

您需要使用 @Provider ，否则永远不会在JAX-RS运行时注册。

You need to annotate your exception mapper with @Provider, otherwise it will never get registered with the JAX-RS runtime.

@Provider
public class UserNotFoundMapper implements
        ExceptionMapper<UserNotFoundException> {
    @Override
    public Response toResponse(UserNotFoundException ex) {
        return Response.status(404).entity(ex.getMessage()).type("text/plain")
                .build();
    }
}

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