什么是第一 - 最后还是阻止？ [英] What comes first - finally or catch block?

问题描述

考虑以下测试用例：

public class Main {

    static int a = 0;

    public static void main(String[] args) {
        try {
            test();
            System.out.println("---");
            test2();
        }
        catch(Exception e) {
            System.out.println(a + ": outer catch");
            a++;
        }
    }

    public static void test()
    {
        try {
            throw new Exception();
        }
        catch (Exception e) {
            System.out.println(a + ": inner catch");
            a++;
        }
        finally {
            System.out.println(a + ": finally");
            a++;
        }
    }

    public static void test2() throws Exception
    {
        try {
            throw new Exception();
        }
        finally {
            System.out.println(a + ": finally");
            a++;
        }
    }
}

输出：

0: inner catch
1: finally
---
2: finally
3: outer catch

为什么在 test（）中有什么解释捕获发生在最后，而在 test2（）它是相反的方式？

What's the explanation for why in test() catch happens before finally while in test2() it's the other way around?

推荐答案

因为 test2（）中的尝试块没有 catch 阻止，只有最后。代码不会跳回调用者进入 catch 然后跳转到最后按照你的想法继续那里。

Because the try block in test2() doesn't have a catch block, only a finally. The code won't "jump back" to the caller to fall into catch and then "jump ahead" to the finally to continue there as you seem to think.

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