正则表达式拆分数字和字母组没有空格 [英] Regex split numbers and letter groups without spaces

问题描述

如果我有一个类似11E12C108N的字符串，它是字母组和数字组的串联，我怎么拆分它们而中间没有分隔符空格字符？

If I have a string like "11E12C108N" which is a concatenation of letter groups and digit groups, how do I split them without a delimiter space character inbetween?

例如，我希望得到的分割为：

For example, I want the resulting split to be:

tokens[0] = "11"
tokens[1] = "E"
tokens[2] = "12"
tokens[3] = "C"
tokens[4] = "108"
tokens[5] = "N"

我现在有这个。

public static void main(String[] args) {

    String stringToSplit = "11E12C108N";

    Pattern pattern = Pattern.compile("\\d+\\D+");
    Matcher matcher = pattern.matcher(stringToSplit);

    while (matcher.find()) {
        System.out.println(matcher.group());
    }
}

这给了我：

11E
12C
108N

我可以让原始的正则表达式一次完成吗？而不是必须在中间令牌上再次运行正则表达式？

Can I make the original regex do a complete split in one go? Instead of having to run the regex again on the intermediate tokens?

推荐答案

使用以下正则表达式，并获取所有匹配项的列表。这将是你要找的。

Use the following regex, and get a list of all matches. That will be what you are looking for.

\d+|\D+

在Java中，我认为代码看起来像这样：

In Java, I think the code would look something like this:

Matcher matcher = Pattern.compile("\\d+|\\D+").matcher(theString);
while (matcher.find())
{
    // append matcher.group() to your list
}

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