谷歌API的地方 - 机器人 [英] Google Places API - android
问题描述
我想提出一个Android应用程序，需要在10km以内在我的本地搜索和使用引脚显示结果到地图上，例如：星巴克，Wallmart，商场等搜索词，我请在我的活动课。而且是明确的：我不想开在谷歌地图搜索，我希望它显示在我自己的应用程序的结果。但我得到一个错误，在执行该搜索code。该错误出现在以下几点：
URL：不能得到解决或不是场 执行：该方法execute（）是未定义的类型型Htt prequest 响应：响应不能得到解决，或者不是一个领域
我使用的三个包： com.mycompany.applicationname =默认的包，主要包含code，包括搜索code com.mycompany.applicationname.Model =包含PlaceAutoComplete，PlacesList，广场等。 com.mycompany.applicationname.PlacesRequests =包含PlaceRequest.java
请帮帮我，我真的需要帮助，感谢这么多提前
这是我用来执行搜索的code：
私有静态最后弦乐PLACES_SEARCH_URL =？https://maps.googleapis.com/maps/api/place/search/json;
私有静态最终布尔PRINT_AS_STRING = FALSE;
公共无效performSearch（）抛出异常{
尝试 {
的System.out.println（执行搜索......）;
的System.out.println（-------------------）;
HTT prequestFactory HTT prequestFactory = createRequestFactory（运输）;
HTT prequest请求= HTT prequestFactory.buildGetRequest（新GenericUrl（PLACES_SEARCH_URL））;
request.url.put（钥匙，API_KEY）;
request.url.put（位置，纬度+，+ LNG）;
request.url.put（半径，500）;
request.url.put（传感器，假）;
如果（PRINT_AS_STRING）{
的System.out.println（request.execute（）parseAsString（））;
} 其他 {
。PlacesList地方= request.execute（）parseAs（PlacesList.class）;
的System.out.println（STATUS =+ places.status）;
对于（地方的地方：places.results）{
的System.out.println（地方）;
}
}
}赶上（Htt的presponseException E）{
通信System.err.println（e.response.parseAsString（））;
扔ê;
}
}
您可以通过使用的谷歌API的Java客户端 - 这是使用Java客户端获取所有的60结果的例子
公共PlacesList搜索（双纬度，双经度，双半径，字符串类型）
抛出异常{
尝试 {
HTT prequestFactory HTT prequestFactory = createRequestFactory（HTTP_TRANSPORT）;
HTT prequest请求= HTT prequestFactory
.buildGetRequest（新GenericUrl（https://maps.googleapis.com/maps/api/place/search/json？））;
。request.getUrl（）把（钥匙，YOUR_API_KEY）;
。request.getUrl（）把（位置，北纬+，+经度）;
。request.getUrl（）把（半径，半径）;
。request.getUrl（）把（传感器，假）;
。request.getUrl（）把（类型，类型）;
。PlacesList列表= request.execute（）parseAs（PlacesList.class）;
如果（list.next_page_token！= NULL || list.next_page_token！=）{
视频下载（4000）;
/ *因为令牌可以后它已经产生一个很短的时间用* /
。request.getUrl（）把（pagetoken，list.next_page_token）;
。PlacesList温度= request.execute（）parseAs（PlacesList.class）;
list.results.addAll（temp.results）;
如果（temp.next_page_token！= NULL || temp.next_page_token！=）{
视频下载（4000）;
。request.getUrl（）把（pagetoken，temp.next_page_token）;
PlacesList tempList = request.execute（）parseAs（PlacesList.class）。
list.results.addAll（tempList.results）;
}
}
返回列表;
}赶上（Htt的presponseException E）{
返回null;
}
}
I am making an android application that needs to search in my local area within 10km and display the results onto a map using pins, For example: "Starbucks", "Wallmart", Shopping mall, etc. The search word that i specify in my activity class. And to be clear: I do NOT want to open the search in Google maps, i want it to display the results inside MY own application. But i get an error at the code that executes the search. The error comes up on the following things:
Url: url cannot be resolved or is not a field Execute: The method execute() is undefined for the type HttpRequest Response: response cannot be resolved or is not a field
I am using three packages: com.mycompany.applicationname = Default package, containing main code, including the search code com.mycompany.applicationname.Model = Containing PlaceAutoComplete, PlacesList, Place, etc. com.mycompany.applicationname.PlacesRequests = Containing PlaceRequest.java
Please help me, i really need help and thanks SO much in advance
This is the code that i am using to execute the search:
private static final String PLACES_SEARCH_URL = "https://maps.googleapis.com/maps/api/place/search/json?";
private static final boolean PRINT_AS_STRING = false;
public void performSearch() throws Exception {
try {
System.out.println("Perform Search ....");
System.out.println("-------------------");
HttpRequestFactory httpRequestFactory = createRequestFactory(transport);
HttpRequest request = httpRequestFactory.buildGetRequest(new GenericUrl(PLACES_SEARCH_URL));
request.url.put("key", API_KEY);
request.url.put("location", lat + "," + lng);
request.url.put("radius", 500);
request.url.put("sensor", "false");
if (PRINT_AS_STRING) {
System.out.println(request.execute().parseAsString());
} else {
PlacesList places = request.execute().parseAs(PlacesList.class);
System.out.println("STATUS = " + places.status);
for (Place place : places.results) {
System.out.println(place);
}
}
} catch (HttpResponseException e) {
System.err.println(e.response.parseAsString());
throw e;
}
}
You can do this by using Google API JAVA Client - Here is an example using the java client for getting all the 60 results.
public PlacesList search(double latitude, double longitude, double radius, String types)
throws Exception {
try {
HttpRequestFactory httpRequestFactory = createRequestFactory(HTTP_TRANSPORT);
HttpRequest request = httpRequestFactory
.buildGetRequest(new GenericUrl("https://maps.googleapis.com/maps/api/place/search/json?"));
request.getUrl().put("key", YOUR_API_KEY);
request.getUrl().put("location", latitude + "," + longitude);
request.getUrl().put("radius", radius);
request.getUrl().put("sensor", "false");
request.getUrl().put("types", types);
PlacesList list = request.execute().parseAs(PlacesList.class);
if(list.next_page_token!=null || list.next_page_token!=""){
Thread.sleep(4000);
/*Since the token can be used after a short time it has been generated*/
request.getUrl().put("pagetoken",list.next_page_token);
PlacesList temp = request.execute().parseAs(PlacesList.class);
list.results.addAll(temp.results);
if(temp.next_page_token!=null||temp.next_page_token!=""){
Thread.sleep(4000);
request.getUrl().put("pagetoken",temp.next_page_token);
PlacesList tempList = request.execute().parseAs(PlacesList.class);
list.results.addAll(tempList.results);
}
}
return list;
} catch (HttpResponseException e) {
return null;
}
}
这篇关于谷歌API的地方 - 机器人的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
