BufferedReader与Console vs Scanner [英] BufferedReader vs Console vs Scanner

问题描述

您好我是 Java 的新手，我想知道在控制台中读取用户输入的最佳选择是什么，据我所知3种方法：

Hi I'm new to Java and I would like to know what is the best choice to read a user Input in the console, as far as I know there are 3 ways to do it:

1. 控制台控制台= System.console（）;


2. BufferedReader输入=新的BufferedReader（新的InputStreamReader（System.in））;


3. 扫描仪阅读器=新扫描仪（System.in）;

1. Console console = System.console();
2. BufferedReader input = new BufferedReader(new InputStreamReader(System.in));
3. Scanner reader = new Scanner(System.in);

哪一个应该我选择？为什么那个而不是其他？

Which one should I choose? Why that one and not the other ones?

推荐答案

BufferedReader

• 自Java 1.1以来


• 抛出已检查的异常


• 可以读取字符，字符数组和行


• 快速



BufferedReader

• Since Java 1.1
• Throws checked exceptions
• Can read chars, char arrays, and lines
• Fast


• 自Java 1.5以来


• 不抛出已检查的异常


• 可以读取行，空格分隔的标记，正则表达式分隔的标记和数字


• 很难阅读单个字符


• Since Java 1.5
• Doesn't throw checked exceptions
• Can read lines, whitespace-delimited tokens, regex-delimited tokens, and numbers
• Difficult to read single characters


• 自Java 1.6以来


• 不抛出已检查的异常


• 可以读取行


• 底层读者可以读取字符和字符数组（在行界限处停止）


• 并非始终可用（例如 Eclipse ）


• 可以读取密码（即阅读而不显示字符）


• Since Java 1.6
• Doesn't throw checked exceptions
• Can read lines
• Underlying reader can read chars and char arrays (stops at line bounds)
• Not always available (e.g. Eclipse)
• Can read passwords (i.e. read without displaying the characters)

方法阅读数字非常有用。例外情况未经检查，因此您不必编写样板try / catch块。

The methods for reading numbers are very useful. The exceptions are unchecked, so you do not have to write boilerplate try/catch blocks.

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