有没有办法在不添加throws声明的情况下抛出异常？ [英] Is there a way to throw an exception without adding the throws declaration?

问题描述

我有以下情况。

我有一个Java类，它继承自另一个基类并覆盖一个方法。
基本方法不会抛出异常，因此没有 throws ... 声明。

I have a Java Class that inherits from another base class and overrides a method. The base method does not throw exceptions and thus has no throws ... declaration.

现在我自己的方法应该能够抛出异常，但我要么选择

Now my own method should be able to throw exception but I either have the choise to

• 吞下异常


• 添加一个抛出声明

两者都不满意，因为第一个会默默地忽略异常（好吧我可以执行一些记录）由于方法标题不同，第二个会产生编译错误。

Both a not satisfying because the first one would silently ignore the exception (ok I could perform some logging) and the second would generate compiler errors because of the different method headers.

public class ChildClass extends BaseClass {

        @Override 
        public void SomeMethod() {
            throw new Exception("Something went wrong");
        }
}

推荐答案

你如果你真的想要，可以抛出未经检查的异常，而不必声明它们。未经检查的异常扩展 RuntimeException 。扩展错误的Throwable也未选中，但只应用于非常严重的问题（例如无效的字节码）。

You can throw unchecked exceptions without having to declare them if you really want to. Unchecked exceptions extend RuntimeException. Throwables that extend Error are also unchecked, but should only be used for really serious issues (such as invalid bytecode).

作为具体案例，Java 8添加了 <$ c包装和重新抛出的$ c> UncheckedIOException IOException 。

As a specific case, Java 8 added UncheckedIOException for wrapping and rethrowing IOException.

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