如何检查生成的zip文件是否已损坏？ [英] How to check if a generated zip file is corrupted?

问题描述

我们有一段代码可以在我们的系统上生成一个zip文件。一切都还可以，但有时这个由FilZip或WinZip打开的zip文件被认为已损坏。

we have a piece of code which generates a zip file on our system. Everything is ok, but sometimes this zip file while opened by FilZip or WinZip is considered to be corrupted.

所以这是我的问题：我们如何以编程方式检查生成zip文件已损坏？

So here is my question: how can we check programatically if a generated zip file is corrupted?

以下是我们用于生成zip文件的代码：

Here is the code we are using to generate our zip files:

try {
    ZipOutputStream zos = new ZipOutputStream(new FileOutputStream(tmpFile));
    byte[] buffer = new byte[16384];
    int contador = -1;
    for (DigitalFile digitalFile : document.getDigitalFiles().getContent()) {
       ZipEntry entry = new ZipEntry(digitalFile.getName());
       FileInputStream fis = new FileInputStream(digitalFile.getFile());
       try {
          zos.putNextEntry(entry);
          while ((counter = fis.read(buffer)) != -1) {
             zos.write(buffer, 0, counter);
          }
          fis.close();
          zos.closeEntry();
       } catch (IOException ex) {
          throw new OurException("It was not possible to read this file " + arquivo.getId());
       }
    }
    try {
      zos.close();
    } catch (IOException ex) {
      throw new OurException("We couldn't close this stream", ex);
    }

我们在这里有什么问题吗？

Is there anything we are doing wrong here?

编辑：
实际上，上面的代码绝对没问题。我的问题是我正在为我的用户重定向错误的流。因此，不是打开一个zip文件，而是打开一些完全不同的东西。 Mea culpa :(

Actually, the code above is absolutely ok. My problem was that I was redirecting the WRONG stream for my users. So, instead of opening a zip file they where opening something completely different. Mea culpa :(

但主要问题仍然存在：如何以编程方式验证给定的zip文件是否未损坏？

BUT the main question remains: how programatically I can verify if a given zip file is not corrupted?

推荐答案

您可以使用 ZipFile 类来检查您的文件：

You can use the ZipFile class to check your file :

 static boolean isValid(final File file) {
    ZipFile zipfile = null;
    try {
        zipfile = new ZipFile(file);
        return true;
    } catch (IOException e) {
        return false;
    } finally {
        try {
            if (zipfile != null) {
                zipfile.close();
                zipfile = null;
            }
        } catch (IOException e) {
        }
    }
}

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